C#窗体程序，创建多个串口的接收和发送的完整代码

在C#中创建一个窗体程序处理多个串口的接收和发送，你需要做的是首先安装`System.IO.Ports`命名空间来访问串口功能，然后编写一个包含多个串口实例的类，并在窗体上添加控件来管理每个串口的状态。下面是一个简化的示例代码：

using System;
using System.IO.Ports;
using System.Threading;

public partial class MainForm : Form
{
    private SerialPort[] serialPorts = new SerialPort[2]; // 假设最多有两个串口

    public MainForm()
    {
        InitializeComponent();
        
        // 初始化串口设置
        for (int i = 0; i < serialPorts.Length; i++)
        {
            serialPorts[i] = new SerialPort();
            serialPorts[i].Name = $"SerialPort_{i + 1}";
            serialPorts[i].DataReceived += SerialPort_DataReceived; // 注册数据接收事件
        }
    }

    private void btnConnect_Click(object sender, EventArgs e)
    {
        foreach (SerialPort port in serialPorts)
        {
            if (!port.IsOpen) // 如果串口未打开
            {
                try
                {
                    port.Open(); // 尝试打开串口
                    btnConnect.Enabled = false; // 防止多次连接
                    Console.WriteLine($"Connected to {port.Name}");
                }
                catch (Exception ex)
                {
                    MessageBox.Show($"Failed to open {port.Name}: {ex.Message}");
                }
            }
        }
    }

    private void btnSend_Click(object sender, EventArgs e)
    {
        string data = txtMessage.Text;
        if (selectedPort.SelectedIndex != -1) // 确保选择了串口
        {
            SerialPort selectedPort = serialPorts[selectedPort.SelectedIndex];
            if (selectedPort.IsOpen)
            {
                selectedPort.Write(data);
                Console.WriteLine($"Sent message to {selectedPort.Name}: {data}");
            }
        }
    }

    private void SerialPort_DataReceived(object sender, SerialDataReceivedEventArgs e)
    {
        SerialPort port = (SerialPort)sender;
        byte[] buffer = new byte[port.BytesToRead];
        port.Read(buffer, 0, buffer.Length);
        textBoxSerialOutput.AppendText($"{DateTime.Now.ToString("HH:mm:ss")} - {port.Name}: {BitConverter.ToString(buffer)}\n");
    }
}