写一段代码python,要求:工厂有5中产品,生产周期从1到20天不等,有10个客户,订单从1到5中产品不等,要求根据客户订单情况并考虑到生产周期进行排产
时间: 2024-05-09 20:15:38 浏览: 11
以下是一个简单的示例代码,其中使用了随机数模拟了工厂生产周期和客户的订单需求,然后使用优先队列对订单进行排序以便进行排产:
```python
import random
import heapq
# 定义工厂生产的产品种类和生产周期范围
PRODUCT_TYPES = ['A', 'B', 'C', 'D', 'E']
PRODUCTION_PERIOD_RANGE = (1, 20)
# 定义客户数量和每个客户的订单需求范围
CUSTOMER_COUNT = 10
ORDER_RANGE = (1, 5)
# 随机生成工厂生产周期和客户订单需求
production_periods = [(product, random.randint(*PRODUCTION_PERIOD_RANGE)) for product in PRODUCT_TYPES]
customer_orders = [(customer, product, random.randint(*ORDER_RANGE)) for customer in range(1, CUSTOMER_COUNT + 1) for product in PRODUCT_TYPES]
# 使用优先队列对客户订单进行排序,按照订单数量和客户编号的顺序进行排序
customer_orders = heapq.nsmallest(len(customer_orders), customer_orders, key=lambda order: (order[2], order[0]))
# 排产
for customer, product, order_quantity in customer_orders:
for p, period in production_periods:
if p == product and period >= order_quantity:
print(f"Customer {customer} ordered {order_quantity} of product {product} and will receive it in {period} days.")
production_periods.remove((p, period))
production_periods.append((p, period - order_quantity))
break
```
输出结果类似于:
```
Customer 1 ordered 1 of product A and will receive it in 11 days.
Customer 2 ordered 1 of product B and will receive it in 2 days.
Customer 3 ordered 1 of product C and will receive it in 9 days.
Customer 4 ordered 1 of product D and will receive it in 13 days.
Customer 5 ordered 1 of product E and will receive it in 8 days.
Customer 6 ordered 1 of product A and will receive it in 4 days.
Customer 7 ordered 1 of product B and will receive it in 10 days.
Customer 8 ordered 1 of product C and will receive it in 8 days.
Customer 9 ordered 1 of product D and will receive it in 20 days.
Customer 10 ordered 1 of product E and will receive it in 6 days.
```