python自动获取当前日期，并绘制对应的七段数码管

以下是Python代码实现自动获取当前日期，并绘制对应的七段数码管：

import time
import turtle

# 定义各数字对应的七段数码管编码
segments = {
    0: [1, 1, 1, 1, 1, 1, 0],
    1: [0, 1, 1, 0, 0, 0, 0],
    2: [1, 1, 0, 1, 1, 0, 1],
    3: [1, 1, 1, 1, 0, 0, 1],
    4: [0, 1, 1, 0, 0, 1, 1],
    5: [1, 0, 1, 1, 0, 1, 1],
    6: [1, 0, 1, 1, 1, 1, 1],
    7: [1, 1, 1, 0, 0, 0, 0],
    8: [1, 1, 1, 1, 1, 1, 1],
    9: [1, 1, 1, 1, 0, 1, 1]
}

# 定义画笔的位置和大小
start_pos = (-250, 0)
segment_size = 50

# 获取当前日期
today = time.strftime("%Y%m%d")

# 创建海龟画笔
pen = turtle.Turtle()
pen.penup()
pen.goto(start_pos)
pen.pendown()

# 逐个绘制日期的数字对应的七段数码管
for i in today:
    for j, on in enumerate(segments[int(i)]):
        pen.penup()
        if j == 0:  # 上横线
            pen.goto(start_pos[0], start_pos[1] + segment_size)
        elif j == 1:  # 右上竖线
            pen.goto(start_pos[0] + segment_size, start_pos[1] + segment_size)
        elif j == 2:  # 右下竖线
            pen.goto(start_pos[0] + segment_size, start_pos[1])
        elif j == 3:  # 下横线
            pen.goto(start_pos[0], start_pos[1] - segment_size)
        elif j == 4:  # 左下竖线
            pen.goto(start_pos[0] - segment_size, start_pos[1])
        elif j == 5:  # 左上竖线
            pen.goto(start_pos[0] - segment_size, start_pos[1] + segment_size)
        elif j == 6:  # 中间横线
            pen.goto(start_pos[0], start_pos[1] + segment_size // 2)
        if on:
            pen.pendown()
            pen.forward(segment_size)
        else:
            pen.penup()
            pen.forward(segment_size)
    start_pos = (start_pos[0] + segment_size * 2, start_pos[1])

# 隐藏画笔
pen.hideturtle()

# 等待用户关闭窗口
turtle.mainloop()

运行结果如下所示：