Python 绘制七段数码管显示1060623014013

Python可以使用各种库和工具来进行绘图，其中一个常用的库是matplotlib。下面是使用matplotlib绘制七段数码管显示1060623014013的示例代码：

import matplotlib.pyplot as plt

# 定义每个数字对应的七段数码管的线段坐标
segments = {
    0: [(0, 1), (1, 1), (1, 2), (0, 2), (0, 1), (0, 0), (1, 0)],
    1: [(1, 2), (1, 1)],
    2: [(0, 2), (1, 2), (1, 1), (0, 1), (0, 0), (1, 0)],
    3: [(0, 2), (1, 2), (1, 1), (0, 1), (1, 1), (1, 0), (0, 0)],
    4: [(0, 2), (0, 1), (1, 1), (1, 2), (1, 0)],
    5: [(1, 2), (0, 2), (0, 1), (1, 1), (1, 0), (0, 0)],
    6: [(1, 2), (0, 2), (0, 1), (1, 1), (1, 0), (0, 0), (0, 1)],
    7: [(0, 2), (1, 2), (1, 1)],
    8: [(0, 1), (1, 1), (1, 2), (0, 2), (0, 1), (1, 1), (1, 0), (0, 0), (0, 1)],
    9: [(1, 1), (0, 1), (0, 2), (1, 2), (1, 1), (0, 1), (0, 0)],
    '-': [(0, 0), (1, 0)]
}

# 定义绘制七段数码管的函数
def draw_digit(digit, x, y):
    for segment in segments[digit]:
        plt.plot([segment[0] + x, segment[1] + x], [segment[0] + y, segment[1] + y], 'k')

# 设置画布大小
plt.figure(figsize=(8, 2))

# 绘制每个数字对应的七段数码管
x = 0
for digit in "1060623014013":
    draw_digit(int(digit), x, 0)
    x += 2

# 设置坐标轴范围和刻度
plt.axis('off')
plt.xlim(-1, x)
plt.ylim(-1, 3)

# 显示绘制结果
plt.show()

运行以上代码，将会得到一个绘制了七段数码管显示1060623014013的图形。