用python绘制七段数码管
时间: 2023-11-19 12:38:26 浏览: 109
Python:绘制七段数码管
下面是一个简单的用Python绘制七段数码管的示例代码:
```python
import turtle
# 定义数字0-9的七段数码管的线段坐标
segments = [
[(0, 60), (-30, 30), (30, 30), (0, 60), (0, 0), (30, -30), (-30, -30), (0, 0)],
[(-20, 50), (20, 50), (10, 40), (-10, 40), (-20, 50), (-20, 10), (20, 10)],
[(20, 50), (20, 30), (-20, 30), (-20, 10), (20, 10), (20, -10), (-20, -10)],
[(20, 30), (20, 50), (-20, 50), (-20, 30), (-20, 10), (20, 10), (20, -10), (-20, -10)],
[(0, 60), (-30, 30), (-30, -30), (0, 0), (30, -30), (30, 30)],
[(20, 50), (-20, 50), (-20, 30), (20, 30), (20, 10), (-20, 10), (-20, -10), (20, -10)],
[(0, 60), (-30, 30), (-30, -30), (0, 0), (30, -30), (30, 30), (0, 30)]
]
# 定义绘制七段数码管的函数
def draw_digit(digit):
turtle.penup()
turtle.goto(0, 0)
turtle.pendown()
for i in range(7):
if i in [0, 3, 6]:
turtle.penup()
else:
turtle.pendown()
if i == 0 and digit in [2, 3, 5, 6, 7, 8, 9]:
turtle.pendown()
if i == 3 and digit in [0, 1, 2, 3, 4, 7, 8, 9]:
turtle.pendown()
if i == 6 and digit in [0, 2, 3, 5, 6, 8, 9]:
turtle.pendown()
x, y = segments[i][0]
turtle.goto(x, y)
for j in range(1, len(segments[i])):
x, y = segments[i][j]
turtle.goto(x, y)
turtle.penup()
# 测试绘制函数
turtle.speed(0)
turtle.pensize(5)
turtle.hideturtle()
for i in range(10):
draw_digit(i)
turtle.penup()
turtle.goto((i + 1) * 80, 0)
turtle.pendown()
turtle.done()
```
该代码使用turtle库绘制七段数码管。首先定义了数字0-9的七段数码管的线段坐标,然后定义了绘制七段数码管的函数。该函数使用turtle库的画笔移动和画笔抬起/放下命令绘制数码管的每一条线段。
最后,测试绘制函数并用循环绘制数字0-9的七段数码管。运行代码后,将会得到如下图所示的结果:
![七段数码管](https://cdn.luogu.com.cn/upload/image_hosting/edj8l7t0.png)
阅读全文