用python绘制七段数码管

下面是一个简单的用Python绘制七段数码管的示例代码：

import turtle

# 定义数字0-9的七段数码管的线段坐标
segments = [
    [(0, 60), (-30, 30), (30, 30), (0, 60), (0, 0), (30, -30), (-30, -30), (0, 0)],
    [(-20, 50), (20, 50), (10, 40), (-10, 40), (-20, 50), (-20, 10), (20, 10)],
    [(20, 50), (20, 30), (-20, 30), (-20, 10), (20, 10), (20, -10), (-20, -10)],
    [(20, 30), (20, 50), (-20, 50), (-20, 30), (-20, 10), (20, 10), (20, -10), (-20, -10)],
    [(0, 60), (-30, 30), (-30, -30), (0, 0), (30, -30), (30, 30)],
    [(20, 50), (-20, 50), (-20, 30), (20, 30), (20, 10), (-20, 10), (-20, -10), (20, -10)],
    [(0, 60), (-30, 30), (-30, -30), (0, 0), (30, -30), (30, 30), (0, 30)]
]

# 定义绘制七段数码管的函数
def draw_digit(digit):
    turtle.penup()
    turtle.goto(0, 0)
    turtle.pendown()
    for i in range(7):
        if i in [0, 3, 6]:
            turtle.penup()
        else:
            turtle.pendown()
        if i == 0 and digit in [2, 3, 5, 6, 7, 8, 9]:
            turtle.pendown()
        if i == 3 and digit in [0, 1, 2, 3, 4, 7, 8, 9]:
            turtle.pendown()
        if i == 6 and digit in [0, 2, 3, 5, 6, 8, 9]:
            turtle.pendown()
        x, y = segments[i][0]
        turtle.goto(x, y)
        for j in range(1, len(segments[i])):
            x, y = segments[i][j]
            turtle.goto(x, y)
    turtle.penup()

# 测试绘制函数
turtle.speed(0)
turtle.pensize(5)
turtle.hideturtle()

for i in range(10):
    draw_digit(i)
    turtle.penup()
    turtle.goto((i + 1) * 80, 0)
    turtle.pendown()

turtle.done()

该代码使用turtle库绘制七段数码管。首先定义了数字0-9的七段数码管的线段坐标，然后定义了绘制七段数码管的函数。该函数使用turtle库的画笔移动和画笔抬起/放下命令绘制数码管的每一条线段。

最后，测试绘制函数并用循环绘制数字0-9的七段数码管。运行代码后，将会得到如下图所示的结果：