已知两个非降序链表序列S1与S2，设计函数构造出S1与S2合并后的新的非降序链表S3。 输入格式: 输入分两行，分别在每行给出由若干个正整数构成的非降序序列，用−1表示序列的结尾（−1不属于这个序列）。数字用空格间隔。

我可以为您提供一个解决方案来合并两个非降序链表S1和S2，构造出新的非降序链表S3。

以下是一个Python实现的示例代码：

class ListNode:
    def __init__(self, val=0, next=None):
        self.val = val
        self.next = next

def merge_sorted_lists(s1, s2):
    dummy = ListNode(-1)  # 创建一个虚拟头结点
    curr = dummy

    while s1 and s2:
        if s1.val <= s2.val:
            curr.next = s1
            s1 = s1.next
        else:
            curr.next = s2
            s2 = s2.next
        curr = curr.next

    # 将剩余的节点接到合并链表的末尾
    if s1:
        curr.next = s1
    if s2:
        curr.next = s2

    return dummy.next

# 读取输入序列
s1 = list(map(int, input().split()))
s2 = list(map(int, input().split()))

# 创建链表并合并
head1 = ListNode(s1[0])
curr1 = head1
for num in s1[1:]:
    curr1.next = ListNode(num)
    curr1 = curr1.next

head2 = ListNode(s2[0])
curr2 = head2
for num in s2[1:]:
    curr2.next = ListNode(num)
    curr2 = curr2.next

merged_head = merge_sorted_lists(head1, head2)

# 打印合并后的链表S3
result = []
curr = merged_head
while curr:
    result.append(curr.val)
    curr = curr.next

print(*result)