用python在图像处理中实现多直线拟合时剔除相似直线
时间: 2023-12-28 08:04:08 浏览: 67
好的,根据你的要求,我给出以下的Python代码供你参考:
```python
import cv2
import numpy as np
# 读取图片
img = cv2.imread('test.jpg')
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
# 边缘检测
edges = cv2.Canny(gray,50,150,apertureSize = 3)
# 霍夫变换检测直线
lines = cv2.HoughLines(edges,1,np.pi/180,200)
# 将直线参数转换为二维坐标
points = []
for i in range(len(lines)):
rho = lines[i][0][0]
theta = lines[i][0][1]
a = np.cos(theta)
b = np.sin(theta)
x0 = a*rho
y0 = b*rho
x1 = int(x0 + 1000*(-b))
y1 = int(y0 + 1000*(a))
x2 = int(x0 - 1000*(-b))
y2 = int(y0 - 1000*(a))
points.append([(x1,y1),(x2,y2)])
# 剔除相似直线
for i in range(len(points)):
for j in range(i+1,len(points)):
k1 = (points[i][1][1]-points[i][0][1])/(points[i][1][0]-points[i][0][0])
k2 = (points[j][1][1]-points[j][0][1])/(points[j][1][0]-points[j][0][0])
if abs(k1-k2) < 0.2:
points[i][0][0] = (points[i][0][0]+points[j][0][0])/2
points[i][0][1] = (points[i][0][1]+points[j][0][1])/2
points[i][1][0] = (points[i][1][0]+points[j][1][0])/2
points[i][1][1] = (points[i][1][1]+points[j][1][1])/2
points[j][0][0] = -1
points[j][0][1] = -1
points[j][1][0] = -1
points[j][1][1] = -1
# 拟合直线
lines = []
for i in range(len(points)):
if points[i][0][0] == -1:
continue
[vx,vy,x,y] = cv2.fitLine(np.array(points[i]),cv2.DIST_L2,0,0.01,0.01)
k = vy/vx
b = y-k*x
x1 = int((-b)/k)
x2 = int((gray.shape[0]-b)/k)
lines.append([(x1,0),(x2,gray.shape[0])])
# 绘制直线
for i in range(len(lines)):
x1 = lines[i][0][0]
y1 = lines[i][0][1]
x2 = lines[i][1][0]
y2 = lines[i][1][1]
cv2.line(img,(x1,y1),(x2,y2),(0,0,255),2)
# 显示图片
cv2.imshow('img',img)
cv2.waitKey(0)
cv2.destroyAllWindows()
```
代码中,首先读取了一张名为`test.jpg`的图片,然后将其转换为灰度图像,并进行边缘检测。接着,利用霍夫变换检测直线,得到一组直线参数。为了剔除相似的直线,我们将每条直线的两个端点转换为二维坐标,并对每一对直线进行比较。如果两条直线的斜率相差不超过 0.2,则将其合并为一条直线。最后,利用拟合直线的方法,对剩余的直线进行拟合,并在原图上绘制直线。
需要注意的是,代码中的相似直线剔除方法仅适用于直线斜率相近的情况。如果需要处理其他情况,可以根据具体需求进行修改。
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