用c语言写一个判断水仙花数的代码

以下是判断水仙花数的C语言代码：

#include <stdio.h>

int main() {
int num, originalNum, remainder, result = 0;

printf("请输入一个三位数：");
scanf("%d", &num);

originalNum = num;

while (originalNum != 0) {
remainder = originalNum % 10;
result += remainder * remainder * remainder;
originalNum /= 10;
}

if (result == num) {
printf("%d 是水仙花数", num);
} else {
printf("%d 不是水仙花数", num);
}

return 0;
}

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用c语言写代码判断水仙花数

Sure, I can help with that! Here is the C code to check whether a number is an Armstrong number:

#include <stdio.h>
#include <math.h>

int main() {
int num, originalNum, remainder, n = 0;
float result = 0.0;

printf("Enter an integer: ");
scanf("%d", &num);

originalNum = num;

// count the number of digits
for (originalNum = num; originalNum != 0; ++n) {
originalNum /= 10;
}

originalNum = num;

// calculate the result
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}

// check whether the number is an Armstrong number
if ((int)result == num) {
printf("%d is an Armstrong number.", num);
}
else {
printf("%d is not an Armstrong number.", num);
}

return 0;
}

Hope that helps!

c语言判断水仙花数代码

下面是c语言判断水仙花数的代码：

#include <stdio.h>

int main() {
    int num, originalNum, remainder, result = 0;

    printf("请输入一个正整数: ");
    scanf("%d", &num);

    originalNum = num;

    while (originalNum != 0) {
        // 计算每一位数字的立方和
        remainder = originalNum % 10;
        result += remainder * remainder * remainder;
        originalNum /= 10;
    }

    // 判断是否为水仙花数
    if (result == num) {
        printf("%d 是水仙花数", num);
    } else {
        printf("%d 不是水仙花数", num);
    }

    return 0;
}

该程序通过循环计算输入的数字的每一位数字的立方和，然后判断是否与原数字相等，如果相等则是水仙花数，否则不是。