Explain 'int func(int x, int (*p)(int))'. exploiting this fucntion to rewrite this program in C programming languag

e.

Sure, I can explain the function 'int func(int x, int (*p)(int))'. This is a function that takes in two arguments - an integer 'x', and a pointer to a function that takes in an integer argument and returns an integer value.

The function itself returns an integer. When you pass in a integer and a function pointer, the function 'func' can use that function pointer to call the function passed as an argument and pass in the integer 'x'. The function then returns the integer value returned by the function passed as an argument.

For example, if we have a function 'int square(int x)' that squares an integer and we pass it as an argument to 'func', we can call it like this:

int square(int x) {
    return x * x;
}

int func(int x, int (*p)(int)) {
    return p(x);
}

int main() {
    int result = func(5, square); // result will be 25
    return 0;
}

In this program, we first define the 'square' function that squares an integer. Then we call 'func' to pass in the integer 5 and the 'square' function pointer. 'func' then calls 'square' with the integer 5 and returns the result (25) to the 'result' variable. Finally, we return 0 to indicate successful completion of the program.