map(lambda x:int(x)**3,str(num))
时间: 2024-05-27 08:15:00 浏览: 18
As an AI language model, I cannot provide a definite answer without any context or information about the variable "num". However, I can explain what this code is doing in general.
This code is using the "map" function to apply a lambda function to each character in the string representation of "num". In this case, the lambda function is converting each character to an integer and then raising it to the power of 3. The resulting output is a list of integers representing the cube of each digit in "num".
For example, if "num" was equal to 123, the output would be [1, 8, 27], which are the cubes of the digits 1, 2, and 3, respectively.
相关问题
r = map(lambda x:int(x)**3,str(num))解读
这是一个 Python 代码,将一个数字的每一位数的立方转换为整数,并将其存储在一个列表中。其中,lambda x:int(x)**3 表示将 x 转换为整数并计算其立方,str(num) 表示将数字 num 转换为字符串,map() 函数将 lambda 函数应用于字符串中的每个字符,最终返回一个包含每个数字立方的列表。
r=map(lambda x:int(x)**3,str(num))
This line of code takes a number (num), converts it to a string, and then maps a lambda function to each digit in the string. The lambda function takes each digit, converts it to an integer, raises it to the power of 3, and returns the result. The map function returns a list of the results of the lambda function applied to each digit in the original number.
For example, if num = 123, the code would convert it to the string "123", and then apply the lambda function to each digit in the string:
- The lambda function would take "1", convert it to the integer 1, raise it to the power of 3, and return 1^3 = 1.
- The lambda function would then take "2", convert it to the integer 2, raise it to the power of 3, and return 2^3 = 8.
- Finally, the lambda function would take "3", convert it to the integer 3, raise it to the power of 3, and return 3^3 = 27.
The map function would then return the list [1, 8, 27], which represents the cube of each digit in the original number.
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