不是一次性把一个人的牌全发掉，而是一轮一轮的发

非常抱歉，我误解了您的要求。以下是按照一轮一轮发牌的Java代码：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class PokerGame {
    public static void main(String[] args) {
        String[] pokerDeck = createPokerDeck();
        List<String>[] playerHands = dealCards(pokerDeck, 3, 5); // 每位玩家发5张牌
        
        // 打印每位用户的手牌
        for (int i = 0; i < playerHands.length; i++) {
            System.out.println("Player " + (i+1) + " hand: " + Arrays.toString(playerHands[i].toArray()));
        }
    }
    
    // 创建扑克牌数组
    public static String[] createPokerDeck() {
        String[] suits = {"红桃", "方片", "梅花", "黑桃"};
        String[] ranks = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};
        
        String[] pokerDeck = new String[suits.length * ranks.length];
        int index = 0;
        
        for (String suit : suits) {
            for (String rank : ranks) {
                pokerDeck[index] = suit + rank;
                index++;
            }
        }
        
        return pokerDeck;
    }
    
    // 发牌给指定人数的用户
    public static List<String>[] dealCards(String[] pokerDeck, int numPlayers, int cardsPerPlayer) {
        List<String>[] playerHands = new ArrayList[numPlayers];
        
        // 初始化每位玩家的手牌列表
        for (int i = 0; i < numPlayers; i++) {
            playerHands[i] = new ArrayList<>();
        }
        
        int deckIndex = 0;
        int currentPlayer = 0;
        
        // 一轮一轮发牌，直到每位玩家都有足够的手牌
        while (playerHands[0].size() < cardsPerPlayer) {
            playerHands[currentPlayer].add(pokerDeck[deckIndex]);
            deckIndex++;
            currentPlayer++;
            
            // 如果当前玩家是最后一位玩家，则回到第一位玩家继续发牌
            if (currentPlayer == numPlayers) {
                currentPlayer = 0;
            }
        }
        
        return playerHands;
    }
}

这段代码将创建一个字符串数组，其中包含了扑克牌的所有牌。然后，它使用`dealCards`方法按照一轮一轮发牌的方式将牌发给指定数量的用户，并将每位用户的手牌打印出来。每位玩家一轮发一张牌，直到每位玩家都有足够的手牌。您可以根据需要修改代码以适应您的需求。