json.decoder.JSONDecodeError: Expecting ',' delimiter: line 7 column 5 (char 75)
时间: 2024-06-12 17:02:11 浏览: 34
JSONDecodeError是指在解析JSON字符串时出现了错误,通常是由于JSON字符串中缺少逗号或者括号不匹配等问题导致的。这个错误信息中的"Expecting ',' delimiter: line 7 column 5 (char 75)"表示在第7行第5列(即字符75)处期望出现逗号作为分隔符,但实际上并没有出现逗号,所以解析器报错了。一般情况下,解决这个问题需要检查JSON字符串中是否存在语法错误,尤其是括号、逗号、引号等字符是否正确使用和匹配。
相关问题
json.decoder.JSONDecodeError: Expecting ',' delimiter: line 75 column 2
JSONDecodeError异常通常发生在解析JSON数据时,Python解析器期望在JSON对象或数组的元素之间看到逗号(','),但未找到逗号或者逗号的位置不正确。根据提供的引用内容,错误信息是"json.decoder.JSONDecodeError: Expecting ',' delimiter: line 75 column 2"。这意味着在JSON数据的第75行第2列位置上缺少了逗号。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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json.decoder.JSONDecodeError: Expecting ':' delimiter: line 1 column 91 (char 90)
json.decoder.JSONDecodeError: Expecting ':' delimiter: line 1 column 91 (char 90)错误的原因是在第一行的第91个字符处缺少了冒号(:)分隔符。
为了解决这个问题,需要在正确的位置添加冒号(:)分隔符。在给定的示例中,冒号(:)应该在 "uid" 键和其对应的值之间添加。正确的JSON字符串应该是:
{ "uid": "1", "data": [ ["数据1", 86, 81], ["曼联", 74, 66], ["利物浦", 69, 99] ] } <span class="em">1</span><span class="em">2</span><span class="em">3</span>
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