f1 = ['00', '00', '01', '00', '02', '80', '03', '00', '04', '33', '05', '33', '06', '33', '07', '0A', '08', 'F4', '10', '00', '11', '74', '12', '56', '13', '00', '14', '00', '20', '00', '21', '02', '22', '42', '23', '00', '24', '00', '25', '02', '26', '33', '27', '5E', '28', '7A', '29', '00', '2A', '00', '2B', '00', '2C', '00', '2D', '01', '2E', '00', '2F', '00', '30', '00', '31', '06', '32', '02', '33', '01', '40', '00', '41', '02', '42', '42', '43', '00', '44', '00', '45', '02', '46', '33', '47', '5E','48','7A','49','00','4A','00','4B','00','4C','00','4D','01','4E','00','4F','00','50','00','51','06','52','02','53','01','60','00','61','02','62','42','63','00','64','00','65','02','66','33','67','5E','68','7A','69','00','6A','00','6B','00','6C','00','6D','01','6E','00','6F','00','70','00','71','06','72','02','73','01'],python怎么不用定义函数的方法按照顺序分成两个数据一组,并把每一组中的十六进制元素变成八位的二进制数据,并且每一位都一分四,按照1对应1111,0对应0000的映射方式
时间: 2023-08-20 16:56:27 浏览: 40
你可以使用以下代码将列表 `f1` 中的元素按顺序分成两个一组,并将每个元素从十六进制转换为八位二进制数据,并进行一分四的映射:
```python
f1 = ['00', '00', '01', '00', '02', '80', '03', '00', '04', '33', '05', '33', '06', '33', '07', '0A', '08', 'F4', '10', '00', '11', '74', '12', '56', '13', '00', '14', '00', '20', '00', '21', '02', '22', '42', '23', '00', '24', '00', '25', '02', '26', '33', '27', '5E', '28', '7A', '29', '00', '2A', '00', '2B', '00', '2C', '00', '2D', '01', '2E', '00', '2F', '00', '30', '00', '31', '06', '32', '02', '33', '01', '40', '00', '41', '02', '42', '42', '43', '00', '44', '00', '45', '02', '46', '33', '47', '5E','48','7A','49','00','4A','00','4B','00','4C','00','4D','01','4E','00','4F','00','50','00','51','06','52','02','53','01','60','00','61','02','62','42','63','00','64','00','65','02','66','33','67','5E','68','7A','69','00','6A','00','6B','00','6C','00','6D','01','6E','00','6F','00','70','00','71','06','72','02','73','01']
binary_data = []
for i in range(0, len(f1), 2):
group = f1[i:i+2]
binary_group = []
for element in group:
binary_element = bin(int(element, 16))[2:].zfill(8)
mapped_element = ""
for bit in binary_element:
if bit == '1':
mapped_element += '1111'
elif bit == '0':
mapped_element += '0000'
binary_group.append(mapped_element)
binary_data.append(binary_group)
print(binary_data)
```
在上述代码中,我们使用一个循环来遍历列表 `f1`,每次迭代时取出两个元素作为一组。然后,我们将每个元素从十六进制转换为八位二进制,并进行一分四的映射。将转换后的二进制数据放入新的列表 `binary_data` 中。
运行代码后,你将得到按顺序分成两个一组,并且转换为八位二进制数据的结果列表 `binary_data`。每个子列表中包含两个元素,即原始列表中的相邻元素的二进制表示,并且每一位都按照一分四的映射方式进行了转换。