有没有其他方法来计算1!+2!+...+n!的结果?
时间: 2023-11-17 12:02:21 浏览: 121
求s=a+aa+aaa+aaaa+aa...a的值.docx
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可以使用循环来计算1!+2!+...+n!的结果。具体方法是,使用一个循环从1到n,每次将当前数的阶乘加到结果中。代码如下所示:
```python
# Python代码
n = 5
result = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
result += factorial
print(result)
```
```java
// Java代码
int n = 5;
int result = 0;
int factorial = 1;
for (int i = 1; i <= n; i++) {
factorial *= i;
result += factorial;
}
System.out.println(result);
```
```c++
// C++代码
#include <iostream>
using namespace std;
int main() {
int n = 5;
int result = 0;
int factorial = 1;
for (int i = 1; i <= n; i++) {
factorial *= i;
result += factorial;
}
cout << result << endl;
return 0;
}
```
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