帮我写一个拔河赛，用pc的两个按键作为双方发力键，通过串口接收按键值，根据双方按键的次数差显示拔河中间标的位置和颜色，超出一定会范围判定为胜方

好的，以下是一个基于串口通信的PC拔河比赛Python代码示例：

import serial
import time

# 初始化串口通信
ser = serial.Serial('COM3', baudrate=9600, timeout=1)

# 定义比赛轮数和比赛时间
num_rounds = 10
round_time = 30  # 秒

# 定义比赛参数
team1_score = 0
team2_score = 0
team1_presses = 0
team2_presses = 0
score_threshold = 5
press_threshold = 3

# 开始比赛
for i in range(num_rounds):
    # 初始化本轮比赛的参数
    team1_presses = 0
    team2_presses = 0
    team1_score = 0
    team2_score = 0
    start_time = time.time()
    
    # 进行本轮比赛
    while (time.time() - start_time) < round_time:
        # 从串口读取按键值
        data = ser.readline().decode().strip()
        
        # 根据按键值更新双方的发力次数
        if data == "1":
            team1_presses += 1
        elif data == "2":
            team2_presses += 1
        
        # 根据双方的发力次数计算得分和中间标的位置
        if abs(team1_presses - team2_presses) >= press_threshold:
            if team1_presses > team2_presses:
                team1_score += 1
            else:
                team2_score += 1
            score_diff = abs(team1_score - team2_score)
            if score_diff >= score_threshold:
                break
                
        # 根据中间标的位置和得分情况显示不同的颜色
        if team1_score > team2_score:
            print("\033[31m{}\033[0m".format("-"*(score_diff//2)), end="")
            print("\033[32m{}\033[0m".format("-"*(score_threshold//2 - score_diff//2)), end="")
        elif team1_score < team2_score:
            print("\033[32m{}\033[0m".format("-"*(score_threshold//2 - score_diff//2)), end="")
            print("\033[31m{}\033[0m".format("-"*(score_diff//2)), end="")
        else:
            print("-"*(score_threshold//2), end="")
        
        # 等待一段时间再继续下一次循环
        time.sleep(0.05)
    
    # 打印本轮比赛的结果
    if team1_score > team2_score:
        print(" Team 1 wins!")
    elif team1_score < team2_score:
        print(" Team 2 wins!")
    else:
        print(" It's a tie!")
    
    # 判断哪支队伍获得了最终的胜利
    if team1_score > team2_score:
        print("Team 1 wins the game!")
        break
    elif team1_score < team2_score:
        print("Team 2 wins the game!")
        break
    elif i == num_rounds - 1:
        print("The game is a tie!")
    else:
        print("The game continues...")

这个代码示例通过串口通信读取PC的两个按键的值，并根据双方按键的次数差异来计算拔河中间标的位置和显示颜色。如果某个队伍在一定时间内的得分超过了设定的阈值，那么该队伍将被宣布为胜利者。在每轮比赛结束后，程序会判断哪支队伍获得了最终的胜利，并打印相应的结果。