linspace c语言实现

在C语言中实现linspace函数的方法如下所示：

#include <stdio.h>
#include <stdlib.h>

double* linspace(double begin, double finish, int number) {
    double interval = (finish - begin) / (number - 1);
    double* array = (double*)malloc(number * sizeof(double));
    
    for (int i = 0; i < number; i++) {
        array[i = begin + i * interval;
        // printf("(%d, %d) %lf\n", i+1, j+1, array[i]);
    }
    
    return array;
}

int main() {
    double begin = 0.0;
    double finish = 1.0;
    int number = 10;
    
    double* result = linspace(begin, finish, number);
    
    for (int i = 0; i < number; i++) {
        printf("%lf ", result[i]);
    }
    
    return 0;
}

这段代码定义了一个linspace函数，该函数接收起始值begin、终止值finish和元素个数number作为参数，并返回一个动态分配的double类型数组。在函数内部，首先计算出等差间隔interval，然后使用malloc函数动态分配一个长度为number的数组。接下来，使用for循环填充数组中的元素，每个元素的值为begin加上相应的间隔。最后，将数组返回给调用者。在main函数中，我们给出了一个示例，使用linspace函数生成了一个从0.0到1.0之间的10个等差数列，并打印出来。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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