提取列表 names = ["刘二", "张三", "李四", "王五", "赵六", "丁七", "周八"]中奇数序号的姓名

可以使用列表切片的方式来提取奇数序号的姓名。在Python中，列表的索引是从0开始的，因此奇数序号的索引为1、3、5等。具体实现方法如下：

names = ["刘二", "张三", "李四", "王五", "赵六", "丁七", "周八"]
odd_names = names[1::2]
print(odd_names)

运行结果为：

['张三', '王五', '丁七']

相关问题

请提取列表 names = ["刘二", "张三", "李四", "王五", "赵六", "丁七", "周八"]中奇数序号的姓名

可以通过循环和切片来提取列表中奇数序号的姓名：

names = ["刘二", "张三", "李四", "王五", "赵六", "丁七", "周八"]
odd_names = []
for i in range(1, len(names), 2):
    odd_names.append(names[i])
print(odd_names)

输出结果为：

['张三', '王五', '丁七']

补充以下代码，要求补充后的代码能用结构体表示8名学生的学号、姓名、语文、数学、英语三门课的成绩，存放在一维数组中（数组元素为结构体），计算每门课的平均成绩，并显示。 #include "stdio.h" struct STUDENT { long int num; char name[20]; float chinese; float maths; float english; }; float average(struct STUDENT a[], int x) { } void outputstu(struct STUDENT a[]) { } void main() { struct STUDENT a[8]={7340001,"丁一",65,72,90,7340002,"刘二",62,46,87,7340003,"张三",56,90,77,7340004,"李四",76,67,65,7340005,"王五",44,88,66,7340006,"陈六",98,78,84,7340007,"赵七",39,40,60,7340008,"郑八",99,72,70}; float chineseavg=0,mathsavg=0,englishavg=0; chineseavg=average(a,1); mathsavg=average(a,2); englishavg=average(a,3); outputstu(a); printf("\n语文平均成绩%6.2f\n数学平均成绩%6.2f\n英语平均成绩%6.2f\n",chineseavg,mathsavg,englishavg); }

#include "stdio.h"

struct STUDENT {
long int num;
char name[20];
float chinese;
float maths;
float english;
};

float average(struct STUDENT a[], int x) {
float sum = 0;
for (int i = 0; i < 8; i++) {
if (x == 1) {
sum += a[i].chinese;
} else if (x == 2) {
sum += a[i].maths;
} else if (x == 3) {
sum += a[i].english;
}
}
return sum / 8;
}

void outputstu(struct STUDENT a[]) {
printf("学号\t\t姓名\t\t语文\t\t数学\t\t英语\n");
for (int i = 0; i < 8; i++) {
printf("%ld\t%s\t\t%.2f\t\t%.2f\t\t%.2f\n", a[i].num, a[i].name, a[i].chinese, a[i].maths, a[i].english);
}
}

void main() {
struct STUDENT a[8] = {
{7340001, "丁一", 65, 72, 90},
{7340002, "刘二", 62, 46, 87},
{7340003, "张三", 56, 90, 77},
{7340004, "李四", 76, 67, 65},
{7340005, "王五", 44, 88, 66},
{7340006, "陈六", 98, 78, 84},
{7340007, "赵七", 39, 40, 60},
{7340008, "郑八", 99, 72, 70},
};
float chineseavg = 0, mathsavg = 0, englishavg = 0;
chineseavg = average(a, 1);
mathsavg = average(a, 2);
englishavg = average(a, 3);
outputstu(a);
printf("\n语文平均成绩%6.2f\n数学平均成绩%6.2f\n英语平均成绩%6.2f\n", chineseavg, mathsavg, englishavg);
}