excel中,B1为最大值,B2为最小值,使用vba生成9个小数点后保留两位的随机数,要求在最大值与最小值之间,且9个数波动范围不能超过0.04并填到C4-C12中
时间: 2024-10-19 20:14:03 浏览: 22
在Excel VBA中,你可以使用`Rnd`函数生成随机数,并结合条件判断来满足你的需求。下面是一个简单的VBA代码示例:
```vba
Sub GenerateRandomNumbers()
Dim max As Double, min As Double, diff As Double
Dim randNum() As Double
Dim i As Integer
' 获取B1和B2的值
max = Range("B1").Value
min = Range("B2").Value
diff = max - min
' 检查波动范围是否大于0.04
If diff < 0.04 Then
MsgBox "波动范围小于0.04,无法生成9个随机数", vbInformation, "警告"
Exit Sub
End If
diff = diff - (diff * 0.04) ' 确保总波动不超过0.04
ReDim randNum(1 To 9) ' 初始化数组大小
For i = 1 To 9
' 生成一个在[min, min+diff]之间的随机数,并四舍五入到小数点后两位
randomNum = Round((min + Rnd() * diff), 2)
Range("C" & (i + 3)).Value = randomNum ' 填充到C列
Next i
End Sub
```
运行此宏后,它将在C4到C12单元格中生成9个在B1和B2值之间波动不超过0.04的小数,并保留两位小数。
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