:selected="selectedValues.indexOf(item.value) !== -1"
时间: 2024-03-02 07:11:59 浏览: 14
这是一个三元表达式,用于判断当前选项是否已经被选中。
如果当前选项的value值在已经选中的值数组(selectedValues)中的索引不为-1,即当前选项已经选中,则:selected属性的值为true,否则为false。
这样就可以根据已经选中的值数组,动态地设置el-option的选中状态。
相关问题
<q-select outlined :options="CompanyCodeOptions" v-model="submitData.CompanyCodes" label="公司代码" dense clearable hint="请选择公司代码" filled emit-value map-options use-input input-debounce="0" :multiple="true" :hide-selected="true" :max-values="50" @filter="filterCompanyCode" :value="submitData.CompanyCodes"></q-select> 在文本框里输入的值会消失
在Quasar的QSelect组件中,输入框中的值会在过滤选项时被重置。这是QSelect组件的默认行为,以便更好地适应选项的过滤。
如果你希望在输入框中保留用户输入的值,可以通过使用 `:use-input.sync` 属性来实现。
下面是修改后的代码示例:
```vue
<template>
<div>
<q-select
outlined
:options="CompanyCodeOptions"
v-model="submitData.CompanyCodes"
label="公司代码"
dense
clearable
hint="请选择公司代码"
filled
emit-value
map-options
:use-input.sync="useInput"
input-debounce="0"
:multiple="true"
:hide-selected="true"
:max-values="50"
@filter="filterCompanyCode"
:value="submitData.CompanyCodes"
></q-select>
</div>
</template>
<script>
export default {
data() {
return {
CompanyCodeOptions: [
// 选项列表...
],
submitData: {
CompanyCodes: [] // 存储选中的值
},
useInput: true // 控制是否使用输入框的值
};
},
methods: {
filterCompanyCode(val, update) {
// 过滤方法的实现...
}
}
};
</script>
```
在上面的代码中,我们添加了一个名为 `useInput` 的响应式数据,并将其绑定到 `:use-input.sync` 属性上。通过设置 `useInput` 的值为 `true`,我们告诉QSelect组件在过滤选项时保留用户输入的值。
通过这种方式,你可以在输入框中保留用户输入的值。
希望这个解决方案对你有所帮助!如果还有其他问题,请随时提问。
优化此代码 const openKeys = ref<string[]>([]) const selectedKeys = ref<string[]>([]) const { currentMenu, currentMenuTree, currentMenuList } = storeToRefs( useLayoutStore(), ) const rootSubmenuKeys = currentMenuList.value.filter((v: any) => { if (v.type === 0) { return v.parentId } }) watch( () => currentMenu, () => { openKeys.value = [currentMenu.value?.parentId] selectedKeys.value = [currentMenu.value?.id] }, { immediate: true }, ) const router = useRouter() /** * 点击事件 * @param e 事件对象 */ const handleClick = (e: any) => { const item = currentMenuList.value.find((_) => _.id === e.key) if (item) { router.push(item.path) } } /** * SubMenu 展开/关闭的回调 * @param e 展开的openKeys */ const onOpenChange = (e: any) => { const latestOpenKey = e.find((key: any) => openKeys.value.indexOf(key) === -1) if (rootSubmenuKeys.indexOf(latestOpenKey) === -1) { openKeys.value = e } else { openKeys.value = latestOpenKey ? [latestOpenKey] : [] } }
There are a few optimizations that could be made to this code:
1. Instead of using `ref` for `openKeys` and `selectedKeys`, you can use `reactive` to make the code more concise:
```
const state = reactive({
openKeys: [],
selectedKeys: [],
})
```
2. Instead of using `storeToRefs` to convert the store state to refs, you can use the `toRefs` function, which is shorter and more concise:
```
const { currentMenu, currentMenuTree, currentMenuList } = toRefs(useLayoutStore())
```
3. Instead of using `watch` to watch the `currentMenu` state changes, you can use a computed property to update the `openKeys` and `selectedKeys` arrays:
```
const selectedMenu = computed(() => {
const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.id)
return [item?.id] || []
})
const parentMenu = computed(() => {
const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.parentId)
return [item?.id] || []
})
watch([selectedMenu, parentMenu], ([selected, parent]) => {
state.selectedKeys = selected
state.openKeys = parent
})
```
4. Instead of using `router.push` in the `handleClick` function, you can use the `router.push` method directly in the template:
```
<Menu.Item :key="item.id" :to="item.path">{{ item.name }}</Menu.Item>
```
5. Finally, instead of using `rootSubmenuKeys` to filter the list of menu items, you can use a computed property to filter the list of menu items based on their type:
```
const subMenuItems = computed(() => {
return currentMenuList.value.filter((v: any) => v.type === 0 && v.parentId)
})
```
By applying these optimizations, the code can be simplified and made more concise.