1023十进制转二进制

以下是C语言实现1023十进制转二进制并统计二进制1的个数的代码示例：

#include <stdio.h>

int main()
{
    int num = 1023;
    int binary[32];
    int i = 0, count = 0;

    while (num > 0) {
        binary[i] = num % 2;
        if (binary[i] == 1) {
            count++;
        }
        num = num / 2;
        i++;
    }

    printf("Binary: ");
    for (int j = i - 1; j >= 0; j--) {
        printf("%d", binary[j]);
    }
    printf("\nCount of 1s: %d\n", count);

    return 0;
}

输出结果为：

Binary: 1111111111
Count of 1s: 10

如果你想在Python中实现1023十进制转二进制，可以使用内置函数bin()，示例代码如下：

num = 1023
binary = bin(num)[2:]
count = binary.count('1')

print("Binary:", binary)
print("Count of 1s:", count)

输出结果为：

Binary: 1111111111
Count of 1s: 10