64位编译器int几个字节
时间: 2023-10-30 22:00:07 浏览: 59
根引用和引用的信息,64位编译器中的int类型通常是4个字节。虽然64位系统本来应该是8个字节的,但为了保持与32位源代码的兼容性,有时会将int类型保持为4个字节。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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- *1* *2* *3* [int类型占几个字节](https://blog.csdn.net/weixin_39932300/article/details/117144731)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT0_1"}}] [.reference_item style="max-width: 100%"]
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相关问题
unsigned long int几个字节
根据引用和引用的信息,unsigned long int在64位编译器下占据8个字节,在32位编译器下占据4个字节。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
- *1* *2* *3* [C语言类型数据所占字节数](https://blog.csdn.net/qq_43378689/article/details/112673595)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT0_1"}}] [.reference_item style="max-width: 100%"]
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unsigned int 占几个字节
根据引用\[1\]和引用\[2\]的信息,unsigned int在不同的编译器和系统中占据的字节数可能不同。在一般情况下,unsigned int在32位编译器中占据4个字节,在64位编译器中占据8个字节。但是根据引用\[3\]的信息,在64位编译器中,unsigned int可能占据4个字节。因此,unsigned int的字节数取决于具体的编译器和系统环境。
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