用Python编写统计及格的同学人数大于平均数的人数
时间: 2024-10-25 15:09:57 浏览: 16
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当你想要用Python编写这样的程序时,首先你需要有一份包含学生分数的数据集,比如每个学生的姓名和成绩。假设数据存储在一个列表或字典中,你可以按照以下步骤操作:
1. **数据准备**:
```python
# 示例数据,实际应用中需要替换为你的数据结构
students = {
"Alice": 85,
"Bob": 90,
"Charlie": 78,
"David": 92,
"Eve": 88
}
```
2. **计算平均分**:
```python
scores = [value for key, value in students.items()] # 提取所有分数
average_score = sum(scores) / len(scores)
```
3. **统计及格(通常认为60分及以上为及格)并筛选**:
```python
passing_scores = {student: score for student, score in students.items() if score > average_score}
```
4. **计算及格且成绩高于平均分的学生人数**:
```python
num_students_above_average = len(passing_scores)
```
完整的代码示例:
```python
students = {
"Alice": 85,
"Bob": 90,
"Charlie": 78,
"David": 92,
"Eve": 88
}
scores = [value for key, value in students.items()]
average_score = sum(scores) / len(scores)
passing_scores = {student: score for student, score in students.items() if score > average_score}
num_students_above_average = len(passing_scores)
print(f"及格且成绩高于平均分的学生有:{num_students_above_average}")
```
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