请帮我写用matlab采用阿基米德正多边形逼近法通过迭代法计算pi的近似值的代码
时间: 2023-03-25 10:04:34 浏览: 60
以下是用matlab采用阿基米德正多边形逼近法通过迭代法计算pi的近似值的代码:
clc;
clear all;
close all;
n = input('请输入正多边形的边数n:');
r = input('请输入正多边形的半径r:');
theta = 2*pi/n;
s = r*sin(theta/2);
p = n*r*sin(theta);
x = r*cos(:theta:2*pi-theta);
y = r*sin(:theta:2*pi-theta);
plot(x,y,'-o');
axis equal;
pi_approx = p/2;
for i = 1:100
n = n*2;
s = sqrt(r^2-s^2);
r_new = sqrt(s^2+(r^2-s^2)/4);
p_new = n*r_new*sin(theta);
pi_approx = p_new/2;
r = r_new;
p = p_new;
end
fprintf('通过阿基米德正多边形逼近法通过迭代法计算得到的pi的近似值为:%f\n',pi_approx);
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