if itme1 == '小学': count = count_conditions( change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '女': count = count_conditions( change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '少数民族': count = count_conditions( change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count代码优化

ChitGPT：您好！关于您的代码，我可以提供一些改进意见。首先，可以将多个if语句合并成一个，以减少冗余代码。具体来说，请尝试以下改进：

count = 0
if itme1 == '小学':
count = count_conditions(change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme)
elif itme1 == '女':
count = count_conditions(change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme)
elif itme1 == '少数民族':
count = count_conditions(change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme)

if count != 0:
sh_3040.cell(index1 7, index 6).value = count

这样可以让代码更加简洁清晰，同时还能提高代码的可读性和可维护性。如果您有任何问题或者需要我帮忙进行其他的改进，欢迎随时告诉我。

相关问题

if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化

:可以考虑将重复使用的代码封装成一个函数，以减少代码重复和提高代码可读性。例如：

def count_by_criteria(teacher_arr, criteria_func, filter_func):
count = count_conditions(teacher_arr, criteria_func, filter_func)
if count != 0:
sh_4149.cell(index1, index).value = count

然后使用这个函数来代替原本重复的代码，例如：

if itme1 == '总计':
count_by_criteria(teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme)
if itme1 == '女':
count_by_criteria(teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme)
if itme1 == '少数民族':
count_by_criteria(teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme)
if itme1 == '在编人员':
count_by_criteria(teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme)

这样代码会更易读和易维护。

for index1, itme1 in enumerate(list_col): for index, itme in enumerate(list_row): if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化

我理解您的问题是如何对上述代码进行优化。这段代码中有多个重复的条件判断语句，可以将其抽取出来，统一处理。同时，可以使用列表推导式简化代码。

以下是优化后的代码：

count_funcs = [
(lambda row: row[9] == '学前' or row[9] == '小学'), # 总计
(lambda row: row[2] == '女'), # 女
(lambda row: row[11] != '汉族'), # 少数民族
(lambda row: row[12] == '是') # 在编人员
]

for index1, item1 in enumerate(list_col):
for index, item in enumerate(list_row):
for count_func in count_funcs:
if item1 == '总计':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
elif item1 == '女':
count = count_conditions(teacher_arr, lambda row: row[2] == '女' and count_func(row), lambda row: row[8] == item)
elif item1 == '少数民族':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
elif item1 == '在编人员':
count = count_conditions(teacher_arr, count_func, lambda row: row[8] == item)
else:
count = 0

if count != 0:
sh_4149.cell(index1 + 6, index + 4).value = count

该代码将条件判断语句抽取出来，存放在一个列表中，然后在循环中依次调用。对于 '女' 这种特殊情况，将其与对应的条件判断函数同时传入 count_conditions 函数中。同时，使用加法替代了 index1 6 和 index 4。列表推导式被用来初始化 count_funcs 列表，使其更加简洁。