#include <iostream> using namespace std;// 定义单链表结构体 struct ListNode { int val; ListNode* next; ListNode(int x) : val(x), next(NULL) { } }; // 定义单链表基本操作函数 class LinkedList { public: // 合并两个有序链表 static ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode dummy(0); ListNode* tail = &dummy; while (l1 && l2) { if (l1->val < l2->val) { tail->next = l1; l1 = l1->next; } else { tail->next = l2; l2 = l2->next; } tail = tail->next; } tail->next = l1 ? l1 : l2; return dummy.next; } }; int main() {// 定义两个有序链表 ListNode* l1 = new ListNode(1); l1->next = new ListNode(2); l1->next->next = new ListNode(4); ListNode* l2 = new ListNode(1); l2->next = new ListNode(3); l2->next->next = new ListNode(4); // 合并两个有序链表 ListNode* mergedList = LinkedList::mergeTwoLists(l1, l2); // 输出结果 while (mergedList) { cout << mergedList->val << " "; mergedList = mergedList->next; } cout << endl; return 0; }该怎么将两个链表变为可输入的

要将两个链表变为可输入的，可以按照以下方式修改代码：

#include <iostream>
using namespace std;

// 定义单链表结构体
struct ListNode {
    int val;
    ListNode* next;
    ListNode(int x) : val(x), next(NULL) { }
};

// 定义单链表基本操作函数
class LinkedList {
public:
    // 合并两个有序链表
    static ListNode* mergeTwoLists(ListNode* l1, ListNode* l2)
    {
        ListNode dummy(0);
        ListNode* tail = &dummy;
        while (l1 && l2) {
            if (l1->val < l2->val) {
                tail->next = l1;
                l1 = l1->next;
            }
            else {
                tail->next = l2;
                l2 = l2->next;
            }
            tail = tail->next;
        }
        tail->next = l1 ? l1 : l2;
        return dummy.next;
    }
};

int main() {
    // 定义两个有序链表，并输入节点的值
    ListNode* l1 = nullptr;
    ListNode* l2 = nullptr;
    int n1, n2;
    cin >> n1 >> n2;  // 分别输入两个链表的节点个数
    for (int i = 0; i < n1; i++) {
        int x;
        cin >> x;
        ListNode* node = new ListNode(x);
        if (l1 == nullptr) {
            l1 = node;
        }
        else {
            ListNode* cur = l1;
            while (cur->next) {
                cur = cur->next;
            }
            cur->next = node;
        }
    }
    for (int i = 0; i < n2; i++) {
        int x;
        cin >> x;
        ListNode* node = new ListNode(x);
        if (l2 == nullptr) {
            l2 = node;
        }
        else {
            ListNode* cur = l2;
            while (cur->next) {
                cur = cur->next;
            }
            cur->next = node;
        }
    }

    // 合并两个有序链表
    ListNode* mergedList = LinkedList::mergeTwoLists(l1, l2);

    // 输出结果
    while (mergedList) {
        cout << mergedList->val << " ";
        mergedList = mergedList->next;
    }
    cout << endl;
    return 0;
}

在修改后的代码中，先输入两个链表的节点个数，然后循环输入每一个节点的值，并根据输入的值构建链表。最后调用合并函数，输出结果。