RSA费马攻击python实现
时间: 2023-12-04 20:39:48 浏览: 90
基于Python实现的RSA算法.zip
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根据提供的引用内容,无法回答RSA费马攻击的Python实现。但是,可以为您提供RSA加密和解密的Python实现。
RSA加密和解密的Python实现如下所示:
```python
import random
def gcd(a, b):
while b != 0:
a, b = b, a % b
return a
def multiplicative_inverse(e, phi):
d = 0
x1 = 0
x2 = 1
y1 = 1
temp_phi = phi
while e > 0:
temp1 = temp_phi//e
temp2 = temp_phi - temp1 * e
temp_phi = e
e = temp2
x = x2 - temp1 * x1
y = d - temp1 * y1
x2 = x1
x1 = x
d = y1
y1 = y
if temp_phi == 1:
return d + phi
def generate_keypair(p, q):
if not (is_prime(p) and is_prime(q)):
raise ValueError("Both numbers must be prime.")
elif p == q:
raise ValueError("p and q cannot be equal")
n = p * q
phi = (p-1) * (q-1)
e = random.randrange(1, phi)
g = gcd(e, phi)
while g != 1:
e = random.randrange(1, phi)
g = gcd(e, phi)
d = multiplicative_inverse(e, phi)
return ((n, e), (n, d))
def encrypt(pk, plaintext):
key, n = pk
cipher = [pow(ord(char), key, n) for char in plaintext]
return cipher
def decrypt(pk, ciphertext):
key, n = pk
plain = [chr(pow(char, key, n)) for char in ciphertext]
return ''.join(plain)
def is_prime(num):
if num == 1:
return False
elif num == 2:
return True
elif num > 2 and num % 2 == 0:
return False
else:
for i in range(3, int(num**0.5)+1, 2):
if num % i == 0:
return False
return True
# 生成公钥和私钥
p = 61
q = 53
public, private = generate_keypair(p, q)
print("公钥:", public)
print("私钥:", private)
# 加密
message = 'Hello World'
encrypted_msg = encrypt(public, message)
print("加密后的消息:", ''.join(map(lambda x: str(x), encrypted_msg)))
# 解密
decrypted_msg = decrypt(private, encrypted_msg)
print("解密后的消息:", decrypted_msg)
print("解密是否正确:", message == decrypted_msg)
```
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