如何用以上=下数据在MATLAB中生成最小配送路径图,起点分别为4、1、1、1、1、1、1、1、4、1,4,5,4,2,2,2,2,2终点分别为5,3,5,6,2,4,8,9,6,7,4,9,3,8,7,5,9,6;距离分别为11,11,14,15,17,18,19,20,21,25,4.6,5.2,9.6,16,17,19,24,45
时间: 2023-06-14 15:06:37 浏览: 44
这是一个典型的最小路径问题,可以使用MATLAB自带的图论工具箱来解决。以下是代码示例:
```matlab
% 定义起点和终点
start_points = [4, 1, 1, 1, 1, 1, 1, 1, 4, 1];
end_points = [5, 3, 5, 6, 2, 4, 8, 9, 6, 7, 4, 9, 3, 8, 7, 5, 9, 6];
% 定义距离矩阵
distances = [
0, 11, 0, 0, 0, 0, 0, 0, 0, 25, 0, 0, 0, 0, 0, 0, 0, 0;
11, 0, 0, 0, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 0, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 4.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 45;
0, 0, 0, 0, 0, 0, 0, 19, 0, 0, 0, 0, 0, 0, 0, 17, 0, 0;
0, 0, 0, 0, 0, 16, 19, 0, 21, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 21, 0, 20, 0, 0, 0, 0, 0, 0, 0, 0;
25, 0, 0, 0, 0, 0, 0, 0, 20, 0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 24, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 24, 0, 9.6, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9.6, 0, 0, 0, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0;
0, 0, 0, 0, 0, 45, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
];
% 创建图对象
G = graph(distances);
% 计算最短路径
for i = 1:length(start_points)
[path, dist] = shortestpath(G, start_points(i), end_points(i));
fprintf("从%d到%d的最短路径为:", start_points(i), end_points(i));
fprintf("%d ", path);
fprintf("\n距离为:%g\n", dist);
end
% 绘制最短路径图
figure;
plot(G, 'EdgeLabel', G.Edges.Weight);
title('最短路径图');
```
该代码会输出每个起点到终点的最短路径和距离,并且会绘制最短路径图。
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