帮我写一个C＃类，实现将复杂的Person类序列化成xml格式，并且能够反序列化为类对象

在C#中，我们可以创建一个`Person`类，并使用`System.Xml.Serialization`命名空间下的特性来实现XML序列化和反序列化。这里是一个简单的例子：

首先，我们定义`Person`类：

using System;
using System.Xml.Serialization;

[XmlRoot("Person")]
public class Person
{
    [XmlElement("FirstName")]
    public string FirstName { get; set; }

    [XmlElement("LastName")]
    public string LastName { get; set; }

    [XmlElement("Age")]
    public int Age { get; set; }

    [XmlElement("Email")]
    public string Email { get; set; }

    [XmlAttribute("Id")] // 如果想作为属性而不是元素，则加上[XmlAttribute]
    public Guid Id { get; set; }

    public Person(string firstName, string lastName, int age, string email, Guid id)
    {
        FirstName = firstName;
        LastName = lastName;
        Age = age;
        Email = email;
        Id = id;
    }
}

然后，我们将一个`Person`对象序列化为XML：

static void SerializePerson(Person person)
{
    var serializer = new XmlSerializer(typeof(Person));
    using (var writer = new System.IO.StringWriter())
    {
        serializer.Serialize(writer, person);
        Console.WriteLine(writer.ToString());
    }
}

// 使用示例
var p = new Person("John", "Doe", 30, "john.doe@example.com", Guid.NewGuid());
SerializePerson(p);

接下来，我们可以从XML字符串反序列化回`Person`对象：

static Person DeserializePerson(string xml)
{
    var serializer = new XmlSerializer(typeof(Person));
    using (var reader = new StringReader(xml))
    {
        return (Person)serializer.Deserialize(reader);
    }
}

// 示例
string xmlString = ... // 从文件或其他源获取XML字符串
var deserializedPerson = DeserializePerson(xmlString);