void fun(int n)
时间: 2023-03-13 17:16:37 浏览: 68
void fun(int n) {
if (n <= 0) {
return;
}
for (int i = 0; i < n; i++) {
printf("这是一个函数,参数为%d\n", n);
}
}
相关问题
void fun(intn,intt)的控制流图
void fun(int n, int t)的控制流图如下:
开始->判断n是否大于t->如果是,执行语句块A->结束
|->如果不是,执行语句块B->判断n是否等于t->如果是,执行语句块C->结束
|->如果不是,执行语句块D->结束
int fun(void)
As an AI language model, I cannot provide a specific implementation for the function `fun()`. However, I can explain some general concepts related to this function.
The function `fun()` is a C function that takes no arguments and returns an integer value. The keyword `void` in the function signature indicates that the function takes no parameters. The purpose and implementation of the function depend on the context in which it is used.
In general, a function can perform a specific task or calculation and return a value that can be used by the calling program. The return value of the `fun()` function can be used for decision-making, error handling, or other purposes, depending on the specific requirements of the program.
To implement the `fun()` function, you would need to define the logic inside the function body, perform any necessary calculations or operations, and return the result using the `return` statement. The specific implementation of the `fun()` function depends on the requirements of the program or application that it is being used in.