单局石头剪刀布python程序

单局石头、剪刀、布游戏的Python程序可以这样编写：

import random

def game():
    choices = ["石头", "剪刀", "布"]
    player_choice = input("请输入你的选择（石头、剪刀或布）：").lower()
    
    if player_choice not in choices:
        print("无效的选择，请重新输入")
        return game()

    computer_choice = random.choice(choices)
    print(f"你选择了{player_choice}，电脑选择了{computer_choice}")

    if player_choice == computer_choice:
        result = "平局"
    elif (player_choice == "石头" and computer_choice == "剪刀") or \
         (player_choice == "剪刀" and computer_choice == "布") or \
         (player_choice == "布" and computer_choice == "石头"):
        result = "你赢了"
    else:
        result = "你输了"

    print(f"游戏结果是：{result}")

# 开始游戏
game()

这个程序首先定义了一个函数`game()`，用户会被提示输入他们的选择，然后电脑随机选择一个。接下来会比较两个选择，根据规则判断胜负，并打印出结果。