用C语言求s=1+1/1!+1/2!+1/3!+...+1/10!。

#include <stdio.h>

int main() {
    int i, j;
    double sum = 1, fac = 1;
    for (i = 1; i <= 10; i++) {
        fac *= i;
        sum += 1.0 / fac;
    }
    printf("s=1+1/1!+1/2!+1/3!+...+1/10!=%f\n", sum);
    return 0;
}