使用c语言求s=1+1/1!+1/2!+1/3!+...+1/N!

#include <stdio.h>

int main() {
int n, i;
double s = 1, factorial = 1;
printf("请输入n的值：");
scanf("%d", &n);
for (i = 1; i <= n; i++) {
factorial *= i; //计算i的阶乘
s += 1 / factorial; //累加1/i!的值
}
printf("s=%f\n", s);
return 0;
}