List<RsysMenu> rootMenus = list.stream().filter(item -> "M".equals(item.getParentId())).sorted().collect(Collectors.toList()); List<RsysMenu> rootMenus = list.stream().filter(item -> "M".equals(item.getParentId())).sorted().collect(Collectors.toList()); List<RsysMenu> rootMenus = list.stream().filter(item -> "M".equals(item.getParentId())).sorted().collect(Collectors.toList()); List<RsysMenu> rootMenus = list.stream().filter(item -> "M".equals(item.getParentId())).sorted().collect(Collectors.toList()); List<RsysMenu> rootMenus = list.stream().filter(item -> "M".equals(item.getParentId())).sorted().collect(Collectors.toList());
时间: 2024-04-13 17:28:57 浏览: 194
这段代码是一个Java代码片段,它的作用是从一个列表中过滤出所有父节点为"M"的菜单项,并按照一定规则进行排序,最后将结果收集到一个新的列表中。
首先,通过使用`stream()`方法将列表转换为流,然后使用`filter()`方法过滤出父节点为"M"的菜单项。接着,使用`sorted()`方法对菜单项进行排序。最后,使用`collect()`方法将过滤和排序后的菜单项收集到一个新的列表中。
请注意,代码中多次出现的重复行是输入错误,应该删除多余的行。正确的代码应该是这样的:
```java
List<RsysMenu> rootMenus = list.stream()
.filter(item -> "M".equals(item.getParentId()))
.sorted()
.collect(Collectors.toList());
```
这样,你就可以得到一个包含所有父节点为"M"的菜单项,并按照排序规则排列的列表。
相关问题
优化这段代码:List<CompletableFuture<CallIntersectionVo>> futureList = Lists.newArrayList(); for (Map.Entry<String, List<String>> entry : intersectionResult.entrySet()) { CompletableFuture<CallIntersectionVo> future = CompletableFuture.supplyAsync(() -> { String account = entry.getKey(); List<String> personNoList = entry.getValue().stream().distinct().collect(Collectors.toList()); CallIntersectionVo vo = new CallIntersectionVo(); if (personNoList.size() >= 2) { List<PersonBasicVo> personVoList = Lists.newArrayList(); int count = 0; for (String personNo : personNoList) { Map<String, Object> callMap = callMapList.stream().filter(map -> personNo.equals(map.get("personNo"))).findAny().get(); List<CallRecord> callList = (List<CallRecord>) callMap.get("callList"); // 统计通话频率 count += callList.stream().filter(x -> account.equals(x.getRelationshipAccount())).count(); // 获取涉案人 personVoList.add(personList.stream().filter(person -> personNo.equals(person.getPersonNo())).findAny().get()); } // 共同号码是否属于涉案人 String commonPersonName = getCommonPersonName(personList, account); if (frequency != null && frequency > 0) { if (count >= frequency) { vo.setPersons(personVoList); vo.setCommonAccount(account); vo.setFrequency(count); vo.setCommonPersonName(commonPersonName); } return vo; } else { vo.setPersons(personVoList); vo.setCommonAccount(account); vo.setFrequency(count); vo.setCommonPersonName(commonPersonName); return vo; } } else { return vo; } }, executor); futureList.add(future); } voList.addAll(futureList.stream().map(CompletableFuture::join) .distinct().sorted(Comparator.comparing(vo -> vo.getPersons().size())) .collect(Collectors.toList()));
优化后的代码如下:
```java
List<CompletableFuture<CallIntersectionVo>> futureList = intersectionResult.entrySet().stream()
.map(entry -> CompletableFuture.supplyAsync(() -> {
String account = entry.getKey();
List<String> personNoList = entry.getValue().stream().distinct().collect(Collectors.toList());
CallIntersectionVo vo = new CallIntersectionVo();
if (personNoList.size() >= 2) {
List<PersonBasicVo> personVoList = personNoList.stream()
.map(personNo -> {
Map<String, Object> callMap = callMapList.stream()
.filter(map -> personNo.equals(map.get("personNo")))
.findAny()
.orElseThrow(() -> new NoSuchElementException("Person not found"));
List<CallRecord> callList = (List<CallRecord>) callMap.get("callList");
int count = (int) callList.stream().filter(x -> account.equals(x.getRelationshipAccount())).count();
return personList.stream()
.filter(person -> personNo.equals(person.getPersonNo()))
.findAny()
.orElseThrow(() -> new NoSuchElementException("Person not found"));
})
.collect(Collectors.toList());
String commonPersonName = getCommonPersonName(personList, account);
vo.setPersons(personVoList);
vo.setCommonAccount(account);
vo.setFrequency(personVoList.size());
vo.setCommonPersonName(commonPersonName);
return vo;
} else {
return vo;
}
}, executor))
.collect(Collectors.toList());
List<CallIntersectionVo> voList = futureList.stream()
.map(CompletableFuture::join)
.distinct()
.sorted(Comparator.comparingInt(vo -> vo.getPersons().size()))
.collect(Collectors.toList());
```
主要优化:
1. 使用流式编程,替换原来的for循环和entrySet遍历。
2. 使用`stream()`和`collect(Collectors.toList())`方法来收集结果,代替手动添加到列表中。
3. 使用`orElseThrow`方法来处理可能找不到元素的情况,避免空指针异常。
4. 将lambda表达式内联,使代码更简洁。
5. 使用`Comparator.comparingInt`方法来指定排序规则,避免编译器警告。
识别代码 @RequestMapping(value = "/common/tree", method = RequestMethod.GET) public ResponseInfo getCommentTree(Integer siteId, @RequestParam Short operator, HttpServletRequest request) throws GlobalException { if (siteId == null) { siteId = SystemContextUtils.getSiteId(request); } final Integer sid = siteId; List<Channel> channels = SystemContextUtils.getUser(request).getChannelsByOperator(siteId, operator); if (channels.size() > 0) { channels = channels.stream() .filter(channel -> !channel.getRecycle() && !channel.getHasDeleted() && channel.getSiteId().equals(sid)) .sorted(Comparator.comparing(Channel::getSortNum) .thenComparing( Comparator.comparing(Channel::getCreateTime))) .collect(Collectors.toList()); } return new ResponseInfo(super.getChildTree(channels, false, "name", "id", "editAble", "createChildAble", "deleteAble", "mergeAble", "staticAble", "permAssignAble", "viewAble")); }
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