select * from ( SELECT t_information.information_id , information_title , published_start_date , published_end_date , information_description , published_flag , popup_flg , t_information.deleted_by , t_information.deleted_at , information_en_title , information_en_description , information_flag FROM t_information left JOIN t_information_en ON t_information.information_id = t_information_en.information_id) a where a.information_id = '76e53a91-c218-48fd-8a40-375993000d06';

根据你提供的SQL查询语句，你想要从两个表（t_information和t_information_en）中选择特定的列，并且通过左连接将它们关联起来。然后，你想要从结果中选择信息ID为'76e53a91-c218-48fd-8a40-375993000d06'的行。以下是查询语句的改进版本：

SELECT
    a.information_id,
    a.information_title,
    a.published_start_date,
    a.published_end_date,
    a.information_description,
    a.published_flag,
    a.popup_flg,
    a.deleted_by,
    a.deleted_at,
    a.information_en_title,
    a.information_en_description,
    a.information_flag
FROM
    (
    SELECT
        t_information.information_id,
        information_title,
        published_start_date,
        published_end_date,
        information_description,
        published_flag,
        popup_flg,
        t_information.deleted_by,
        t_information.deleted_at,
        information_en_title,
        information_en_description,
        information_flag
    FROM
        t_information 
    LEFT JOIN t_information_en ON t_information.information_id = t_information_en.information_id
    ) a
WHERE
    a.information_id = '76e53a91-c218-48fd-8a40-375993000d06';

这个查询语句将返回符合条件的特定信息ID的行，并包含所选择的列。请注意，我对查询进行了格式化，以便更清晰地阅读和理解。如果有任何其他问题，请随时提问！