用C语言实现集合的交集运算

这里提供一种基于数组实现的集合交集运算的C语言代码：

#include <stdio.h>

#define MAX_SIZE 100

int main() {
    int set1[MAX_SIZE], set2[MAX_SIZE], intersection[MAX_SIZE];
    int size1, size2, size_intersection = 0;
    // 输入集合1
    printf("Enter the size of set1: ");
    scanf("%d", &size1);
    printf("Enter the elements of set1: ");
    for (int i = 0; i < size1; i++) {
        scanf("%d", &set1[i]);
    }
    // 输入集合2
    printf("Enter the size of set2: ");
    scanf("%d", &size2);
    printf("Enter the elements of set2: ");
    for (int i = 0; i < size2; i++) {
        scanf("%d", &set2[i]);
    }
    // 计算交集
    for (int i = 0; i < size1; i++) {
        for (int j = 0; j < size2; j++) {
            if (set1[i] == set2[j]) {
                intersection[size_intersection] = set1[i];
                size_intersection++;
                break;
            }
        }
    }
    // 输出交集
    printf("Intersection of set1 and set2: { ");
    for (int i = 0; i < size_intersection; i++) {
        printf("%d ", intersection[i]);
    }
    printf("}\n");
    return 0;
}

该程序先让用户输入两个集合，然后使用两个嵌套循环计算它们的交集，最后输出交集。需要注意的是，该程序假设输入的集合中不含有重复元素。