如何编写一个基本的井字棋（Tic-Tac-Toe）游戏的编程代码？

编写一个基本的井字棋游戏，可以用简单的控制台应用或图形化界面。这里是一个基本的Python控制台版井字棋的示例代码：

import os

# 定义棋盘大小
CH_BOARD_SIZE = 3

def draw_board(board):
    print('-------------')
    for row in board:
        print('|', ' | '.join(row), '|')
        print('--')

def check_win(board, player):
    # 检查每行、每列和两条对角线
    for i in range(CH_BOARD_SIZE):
        if all(board[i][j] == player for j in range(CH_BOARD_SIZE)):
            return True
        if all(board[j][i] == player for j in range(CH_BOARD_SIZE)):
            return True

    # 对角线检查
    if (board[0][0] == player and board[1][1] == player and board[2][2] == player) or \
       (board[0][2] == player and board[1][1] == player and board[2][0] == player):
        return True

    return False

def tic_tac_toe():
    board = [[' ']*CH_BOARD_SIZE for _ in range(CH_BOARD_SIZE)]
    current_player = 'X'

    while True:
        draw_board(board)
        row = int(input(f"{current_player}, 请输入行（0-{CH_BOARD_SIZE-1}）: "))
        col = int(input(f"请输入列（0-{CH_BOARD_SIZE-1}）: "))

        if board[row][col] != ' ':
            print("该位置已被占据，换别人吧！")
            continue

        board[row][col] = current_player
        if check_win(board, current_player):
            print(f"{current_player} 获胜！")
            break

        current_player = 'O' if current_player == 'X' else 'X'

tic_tac_toe()

这个代码实现了单人游戏，每次轮到玩家输入时，检查其输入的位置是否为空，然后更新棋盘状态并检查是否有人赢得比赛。当你运行这个程序时，它会交替显示X和O的玩家。