帮我编写一个简单的贪吃蛇代码
时间: 2023-08-05 19:02:58 浏览: 41
好的,以下是一个简单的贪吃蛇代码,基于Python的pygame库:
```python
import pygame
import random
# 初始化pygame
pygame.init()
# 设置游戏窗口大小
window_width = 400
window_height = 400
window = pygame.display.set_mode((window_width, window_height))
pygame.display.set_caption("贪吃蛇")
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
green = (0, 255, 0)
blue = (0, 0, 255)
# 定义蛇和食物大小
block_size = 10
# 定义游戏时钟
clock = pygame.time.Clock()
# 定义字体
font = pygame.font.SysFont(None, 25)
# 显示消息函数
def message_to_screen(msg, color):
screen_text = font.render(msg, True, color)
window.blit(screen_text, [window_width/6, window_height/3])
# 蛇的移动函数
def snake(block_size, snake_list):
for x,y in snake_list:
pygame.draw.rect(window, green, [x, y, block_size, block_size])
# 游戏主函数
def gameLoop():
gameExit = False
gameOver = False
# 定义蛇的起始位置
lead_x = window_width / 2
lead_y = window_height / 2
# 定义蛇的移动方向
lead_x_change = 0
lead_y_change = 0
# 定义蛇的初始长度
snake_list = []
snake_length = 1
# 定义食物的初始位置
food_x = round(random.randrange(0, window_width - block_size) / 10.0) * 10.0
food_y = round(random.randrange(0, window_height - block_size) / 10.0) * 10.0
while not gameExit:
while gameOver == True:
window.fill(white)
message_to_screen("游戏结束,按Q退出或者按C重新开始", red)
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q:
gameExit = True
gameOver = False
if event.key == pygame.K_c:
gameLoop()
# 处理事件
for event in pygame.event.get():
if event.type == pygame.QUIT:
gameExit = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
lead_x_change = -block_size
lead_y_change = 0
elif event.key == pygame.K_RIGHT:
lead_x_change = block_size
lead_y_change = 0
elif event.key == pygame.K_UP:
lead_y_change = -block_size
lead_x_change = 0
elif event.key == pygame.K_DOWN:
lead_y_change = block_size
lead_x_change = 0
# 判断蛇是否撞到边界
if lead_x >= window_width or lead_x < 0 or lead_y >= window_height or lead_y < 0:
gameOver = True
# 计算蛇的位置并绘制
lead_x += lead_x_change
lead_y += lead_y_change
window.fill(white)
pygame.draw.rect(window, red, [food_x, food_y, block_size, block_size])
snake_head = []
snake_head.append(lead_x)
snake_head.append(lead_y)
snake_list.append(snake_head)
if len(snake_list) > snake_length:
del snake_list[0]
for segment in snake_list[:-1]:
if segment == snake_head:
gameOver = True
snake(block_size, snake_list)
pygame.display.update()
# 判断是否吃到食物
if lead_x == food_x and lead_y == food_y:
food_x = round(random.randrange(0, window_width - block_size) / 10.0) * 10.0
food_y = round(random.randrange(0, window_height - block_size) / 10.0) * 10.0
snake_length += 1
# 控制每秒钟的帧数
clock.tick(15)
pygame.quit()
quit()
gameLoop()
```
这是一个简单的贪吃蛇代码,你可以根据自己的需求进行修改和扩展。
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