写一个手势识别的代码,用python实现
时间: 2024-05-03 14:21:01 浏览: 91
好的,我理解您的要求了。以下是一个简单的手势识别代码,用 Python 实现:
```python
import cv2
import numpy as np
# 读取视频
cap = cv2.VideoCapture(0)
# 定义区域
top, right, bottom, left = 170, 320, 310, 560
# 循环帧
while True:
# 读取帧
ret, frame = cap.read()
# 翻转画面
frame = cv2.flip(frame, 1)
# 绘制边框
cv2.rectangle(frame, (left, top), (right, bottom), (0, 255, 0), 2)
# 显示画面
cv2.imshow('frame', frame)
# 截取ROI
roi = frame[top:bottom, left:right]
# 预处理
gray = cv2.cvtColor(roi, cv2.COLOR_BGR2GRAY)
blur = cv2.GaussianBlur(gray, (5, 5), 0)
thresh = cv2.threshold(blur, 50, 255, cv2.THRESH_BINARY_INV)[1]
# 寻找轮廓
contours, hierarchy = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
# 如果有轮廓
if len(contours) > 0:
# 找到最大轮廓
contour = max(contours, key=cv2.contourArea)
# 判断是否大于一定阈值
if cv2.contourArea(contour) > 3000:
# 绘制轮廓
cv2.drawContours(roi, [contour], 0, (0, 255, 0), 2)
# 找到凸包
hull = cv2.convexHull(contour)
# 找到凸包缺陷
defects = cv2.convexityDefects(contour, cv2.convexHull(contour, returnPoints=False))
# 计算缺陷数量
count_defects = 0
if defects is not None:
for i in range(defects.shape[0]):
s, e, f, d = defects[i, 0]
start = tuple(contour[s][0])
end = tuple(contour[e][0])
far = tuple(contour[f][0])
# 计算缺陷角度
a = np.sqrt((end[0] - start[0]) ** 2 + (end[1] - start[1]) ** 2)
b = np.sqrt((far[0] - start[0]) ** 2 + (far[1] - start[1]) ** 2)
c = np.sqrt((end[0] - far[0]) ** 2 + (end[1] - far[1]) ** 2)
angle = np.arccos((b ** 2 + c ** 2 - a ** 2) / (2 * b * c)) * 180 / np.pi
if angle <= 90:
count_defects += 1
cv2.circle(roi, far, 1, (0, 0, 255), -1)
# 判断结果
if count_defects == 1:
cv2.putText(frame, "One", (50, 50), cv2.FONT_HERSHEY_SIMPLEX, 2, 2)
elif count_defects == 2:
cv2.putText(frame, "Two", (50, 50), cv2.FONT_HERSHEY_SIMPLEX, 2, 2)
elif count_defects == 3:
cv2.putText(frame, "Three", (50, 50), cv2.FONT_HERSHEY_SIMPLEX, 2, 2)
elif count_defects == 4:
cv2.putText(frame, "Four", (50, 50), cv2.FONT_HERSHEY_SIMPLEX, 2, 2)
else:
cv2.putText(frame, "Hello", (50, 50), cv2.FONT_HERSHEY_SIMPLEX, 2, 2)
# 等待按键
k = cv2.waitKey(1) & 0xFF
# 如果按下 ESC 键则退出循环
if k == 27:
break
# 释放视频
cap.release()
# 销毁窗口
cv2.destroyAllWindows()
```
这个代码可以进行手势识别,根据手指数量和姿势给出相应的文字信息,如 "One"、"Two"、"Three" 和 "Four",希望对您有帮助!
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