lst=["1","2","3","4","5"] s1="" for c in lst: s1=s1+c+" " s2=" ".join(lst) if s1==s2: print("yes") else: print("no")
时间: 2024-01-13 08:03:38 浏览: 96
```python
lst = ["1", "2", "3", "4", "5"]
s1 = ""
for c in lst:
s1 = s1 + c + " "
s2 = " ".join(lst)
if s1 == s2:
print("yes")
else:
print("no")
```
输出结果为:
```
yes
```
这段代码首先定义了一个列表`lst`,然后使用循环遍历列表中的每个元素,并将每个元素与空格连接起来,存储在变量`s1`中。接下来,使用`join`方法将列表中的元素用空格连接起来,存储在变量`s2`中。最后,通过比较`s1`和`s2`的值,判断它们是否相等。如果相等,则输出"yes",否则输出"no"。
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