Linux lcd画圆
时间: 2023-11-18 21:03:14 浏览: 205
在Linux中,可以使用SDL库来画圆。以下是一个简单的示例程序,它使用SDL库来在屏幕上绘制一个圆形。
```c
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <stdbool.h>
#include <math.h>
#include <SDL2/SDL.h>
#define SCREEN_WIDTH 640
#define SCREEN_HEIGHT 480
int main(int argc, char* argv[]) {
if (SDL_Init(SDL_INIT_VIDEO) != 0) {
fprintf(stderr, "SDL_Init failed: %s\n", SDL_GetError());
return EXIT_FAILURE;
}
SDL_Window* window = SDL_CreateWindow(
"Circle Drawing",
SDL_WINDOWPOS_UNDEFINED,
SDL_WINDOWPOS_UNDEFINED,
SCREEN_WIDTH,
SCREEN_HEIGHT,
SDL_WINDOW_SHOWN);
if (!window) {
fprintf(stderr, "SDL_CreateWindow failed: %s\n", SDL_GetError());
return EXIT_FAILURE;
}
SDL_Renderer* renderer = SDL_CreateRenderer(
window,
-1,
SDL_RENDERER_ACCELERATED | SDL_RENDERER_PRESENTVSYNC);
if (!renderer) {
fprintf(stderr, "SDL_CreateRenderer failed: %s\n", SDL_GetError());
SDL_DestroyWindow(window);
SDL_Quit();
return EXIT_FAILURE;
}
SDL_Event event;
bool quit = false;
while (!quit) {
while (SDL_PollEvent(&event)) {
if (event.type == SDL_QUIT) {
quit = true;
}
}
// Clear the screen.
SDL_SetRenderDrawColor(renderer, 0, 0, 0, 255);
SDL_RenderClear(renderer);
// Draw a circle.
int radius = 100;
int cx = SCREEN_WIDTH / 2;
int cy = SCREEN_HEIGHT / 2;
SDL_SetRenderDrawColor(renderer, 255, 255, 255, 255);
for (int x = -radius; x <= radius; x++) {
int y = sqrt(radius * radius - x * x);
SDL_RenderDrawPoint(renderer, cx + x, cy + y);
SDL_RenderDrawPoint(renderer, cx + x, cy - y);
}
// Update the screen.
SDL_RenderPresent(renderer);
}
SDL_DestroyRenderer(renderer);
SDL_DestroyWindow(window);
SDL_Quit();
return EXIT_SUCCESS;
}
```
这个程序首先初始化SDL库,然后创建一个窗口和一个渲染器。在主循环中,它绘制一个圆形,并在屏幕上显示它。要绘制圆形,程序使用了圆的标准方程x^2 + y^2 = r^2,然后使用for循环遍历圆的所有x值,并计算相应的y值。最后,程序使用SDL_RenderDrawPoint函数在屏幕上绘制圆上的点。
请注意,如果您要在嵌入式系统或其他非桌面系统上运行此程序,则需要使用适当的SDL库版本,并相应地更改窗口和渲染器的创建代码。
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