Incompatible pointer types initializing 'SeqString *' with an expression of type 'char [6]'，说中文

这个错误提示是因为你尝试用一个类型为 'char [6]' 的表达式来初始化类型为 'SeqString *' 的指针变量。这两个类型不兼容，导致编译器报错。要解决这个问题，你可以考虑将 'char [6]' 类型的表达式转换为 'SeqString *' 类型。具体的解决方法取决于你的代码逻辑和实际需求。

相关问题

Incompatible pointer to integer conversion initializing 'char' with an expression of type 'char[20]'

This error occurs when you try to initialize a variable of type 'char' with an expression of type 'char[20]'.

For example:

char str[20] = "Hello World";
char c = str;

In this code, the variable 'c' is of type 'char', but we are trying to initialize it with the array 'str', which is of type 'char[20]'. This is not allowed in C/C++, hence the error message.

To fix this error, you need to either change the type of the variable 'c' to 'char[20]', or assign a single character from the array 'str' to 'c' using its index.

For example:

char str[20] = "Hello World";
char c = str[0]; // assign the first character of the array to 'c'

Or:

char str[20] = "Hello World";
char c[20];
strcpy(c, str); // copy the contents of 'str' to 'c'

incompatible pointer to integer conversion initializing 'char' with an expression of type 'char[5]' [-Wint-conversion]

在初始化时使用类型为 'char[5]' 的表达式来初始化 'char' 类型的变量，导致指针与整数类型不兼容的转换。这可能是因为您正尝试将一个字符数组赋值给一个字符变量。要解决这个问题，您可以考虑使用字符串复制函数（如 strcpy）来将字符数组的内容复制到字符变量中，或者使用正确的数据类型来存储字符数组的内容。