For the acquisition stage of a given GNSS receiver, the following parameter are known:· T. = 2 code periods· C/N,= 45dB-Hz Front-end bandwidth: B = 4MHz Sampling frequency: fs = 16MHz Determine, in case of GPS L1-C/A signal, the detection threshold to be applied in case of a serial search in order to obtain a false alarm probability Pr=0.001. For the acquisition stage of a given GNSS receiver, the following parameter are known:· T. = 2 code periods· C/N,= 45dB-Hz Front-end bandwidth: B = 4MHz Sampling frequency: fs = 16MHz Determine, in case of GPS L1-C/A signal, the detection threshold to be applied in case of a serial search in order to obtain a false alarm probability Pr=0.001. 请把他翻译成中文并给出解答
时间: 2024-04-08 11:31:48 浏览: 46
对于给定的 GNSS 接收机的获取阶段,已知以下参数:
T = 2个码元
C/N0 = 45dB-Hz
前端带宽:B = 4MHz
采样频率:fs = 16MHz
在进行串行搜索时,为了获得虚警概率 Pr = 0.001,需要确定应用的检测阈值。
首先,我们需要计算信噪比(SNR)。
SNR(信噪比)可以通过以下公式计算:
SNR = C/N0 + 10log10(B)
其中,C/N0 是以 dB-Hz 为单位的信号功率与噪声功率密度之比,B 是前端带宽。
将已知参数代入公式:
SNR = 45 + 10log10(4) ≈ 55dB
接下来,我们需要计算检测阈值。
检测阈值可以通过以下公式计算:
检测阈值 = (SNR / 2) - 10log10(T) + 10log10(fs)
将已知参数代入公式:
检测阈值 = (55 / 2) - 10log10(2) + 10log10(16) ≈ 28.8 dB-Hz
因此,在进行串行搜索时,为了获得虚警概率 Pr = 0.001,需要应用的检测阈值约为 28.8 dB-Hz。
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