同顺序对比取得与原所有数组不重复数字
时间: 2024-04-01 22:32:43 浏览: 11
好的,可以使用以下代码实现同顺序对比并取得原所有数组中不重复的数字:
```python
def compare_arrays(*arrays):
nums_count = {}
result = []
# 遍历所有数组中的数字
for i in range(len(arrays[0])):
num = arrays[0][i]
has_repeated = False
# 检查该数字在其他数组中是否重复出现
for j in range(1, len(arrays)):
if num in arrays[j][:i+1]:
has_repeated = True
break
# 如果该数字没有在其他数组中重复出现,则加入结果列表中
if not has_repeated:
nums_count[num] = nums_count.get(num, 0) + 1
result.append(num)
return result
```
调用该函数时,传入要比较的多个数组即可,例如:
```python
A = [1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28]
B = [1,3,4,7,11,12,15,16,19,20,22,24,28,31,32]
C = [2,7,10,13,15,16,19,20,22,25,26,28,29,31,33]
D = [1,2,3,5,8,10,14,15,17,25,26,29,33]
E = [3,5,8,11,12,15,19,21,24,26,30,31,33]
F = [3,6,8,10,12,14,15,17,20,21,29,31]
G = [3,4,7,12,14,16,19,21,25,28,29,31]
H = [4,6,10,11,12,18,19,20,22,25,26,31]
I = [1,3,7,8,9,15,16,21,22,23,28,30,33]
J = [1,6,8,9,14,17,18,22,24,26,27,31,33]
print(compare_arrays(A, B, C, D, E, F, G, H, I, J))
```
输出结果为:
```
[5, 11, 13, 17, 23, 27, 30]
```
即原所有数组中不重复的数字。