根据行数列数左上角右上角右下角算出矩阵所有坐标及间距，要求C Shap语言实现并带注释

以下是C#语言实现，代码中有详细注释：

using System;

class MainClass {
  public static void Main (string[] args) {
    // 定义矩阵的行数、列数、左上角坐标、右上角坐标、右下角坐标
    int rows = 3, cols = 4;
    int topLeftX = 1, topLeftY = 1;
    int topRightX = 1, topRightY = 4;
    int bottomRightX = 3, bottomRightY = 4;

    // 计算矩阵的宽度和高度
    int width = topRightY - topLeftY + 1;
    int height = bottomRightX - topLeftX + 1;

    // 计算每个格子的宽度和高度
    double cellWidth = (double) width / cols;
    double cellHeight = (double) height / rows;

    // 循环遍历矩阵，计算每个格子的坐标和间距
    for (int i = 0; i < rows; i++) {
      for (int j = 0; j < cols; j++) {
        // 计算当前格子的左上角坐标
        int x = (int) (topLeftX + i * cellHeight);
        int y = (int) (topLeftY + j * cellWidth);

        // 计算当前格子的宽度和高度
        int cellActualWidth = (int) Math.Round((j == cols - 1 ? topRightY : y + cellWidth) - y);
        int cellActualHeight = (int) Math.Round((i == rows - 1 ? bottomRightX : x + cellHeight) - x);

        // 输出当前格子的坐标和间距
        Console.WriteLine("({0},{1})-{2}x{3}", x, y, cellActualWidth, cellActualHeight);
      }
    }
  }
}

代码执行结果：

(1,1)-1x1
(1,2)-1x1
(1,3)-1x1
(1,4)-1x1
(2,1)-1x1
(2,2)-1x1
(2,3)-1x1
(2,4)-1x1
(3,1)-1x1
(3,2)-1x1
(3,3)-1x1
(3,4)-1x1