SELECT t2.city_name, COUNT(*) AS count FROM ( SELECT cuid FROM ( SELECT cuid, ROW_NUMBER() OVER (PARTITION BY cuid ORDER BY cuid) AS rn FROM map_huiyan_short_stay WHERE loc_x > 12993523 AND loc_x < 13012467 AND loc_y > 4773079 AND loc_y < 4789463 AND event_day = 20230605 ) sub WHERE rn = 1 ) t1 JOIN ( SELECT cuid, city_name FROM map_huiyan_long_stay_with_area WHERE event_day = 20230605 AND event_type = 'home' AND event_os = 'android' ) t2 ON t1.cuid = t2.cuid GROUP BY t2.city_name;修改这段代码使其能在hive中运行
时间: 2024-04-08 07:28:56 浏览: 12
在Hive中运行该代码,需要进行一些修改。Hive不支持使用ROW_NUMBER()函数和子查询的嵌套,因此我们需要使用其他方法来实现相同的功能。
以下是修改后的代码:
```sql
SELECT t2.city_name, COUNT(*) AS count
FROM (
SELECT cuid, MIN(cuid) AS min_cuid
FROM map_huiyan_short_stay
WHERE loc_x > 12993523 AND loc_x < 13012467 AND loc_y > 4773079 AND loc_y < 4789463 AND event_day = 20230605
GROUP BY cuid
) t1
JOIN (
SELECT cuid, city_name
FROM map_huiyan_long_stay_with_area
WHERE event_day = 20230605 AND event_type = 'home' AND event_os = 'android'
) t2 ON t1.min_cuid = t2.cuid
GROUP BY t2.city_name;
```
这里我们使用GROUP BY和MIN()函数来找到每个cuid的最小值,以代替ROW_NUMBER()函数。然后将结果与长期停留表进行连接,并按城市名进行分组。
请确保将map_huiyan_short_stay和map_huiyan_long_stay_with_area替换为您实际使用的表名,并根据需要更改其他条件。