字符串间多个空格变为一个空格: d_45 d_44 d_43 d_42 d_41 d_40 d_39 d_38 d_37 d_36 d_35 d_34 d_33 d_32 d_31 d_30 d_29 d_28 d_27 d_26 d_25 d_24 d_23 d_22 d_21 d_20 d_19 d_18 d_17 d_16 d_15 d_14 d_13 d_12 d_11 d_10 d_9
时间: 2023-08-12 22:05:14 浏览: 67
你的问题是如何把字符串间的多个空格变为一个空格,我理解了。你可以使用正则表达式来实现。在Python中,可以使用re模块来处理正则表达式。以下是示例代码:
```
import re
s = "d_45 d_44 d_43 d_42 d_41 d_40 d_39 d_38 d_37 d_36 d_35 d_34 d_33 d_32 d_31 d_30 d_29 d_28 d_27 d_26 d_25 d_24 d_23 d_22 d_21 d_20 d_19 d_18 d_17 d_16 d_15 d_14 d_13 d_12 d_11 d_10 d_9"
s = re.sub(r'\s+', ' ', s)
print(s)
```
这将输出:d_45 d_44 d_43 d_42 d_41 d_40 d_39 d_38 d_37 d_36 d_35 d_34 d_33 d_32 d_31 d_30 d_29 d_28 d_27 d_26 d_25 d_24 d_23 d_22 d_21 d_20 d_19 d_18 d_17 d_16 d_15 d_14 d_13 d_12 d_11 d_10 d_9
在这段代码中,我们使用了re.sub()函数来把多个空格替换成一个空格。其中正则表达式r'\s+'匹配一个或多个空格,然后把它们替换成一个空格。这样就把字符串间的多个空格变为一个空格了。