RANSAC算法来拟合圆形模型C++
时间: 2023-08-18 17:03:52 浏览: 187
RANSAC(Random Sample Consensus)算法是一种基于统计原理的模型拟合方法,可以用于拟合圆形模型。以下是一个用C++实现RANSAC算法拟合圆形模型的示例代码:
```cpp
#include <iostream>
#include <vector>
#include <random>
#include <cmath>
// 定义圆形结构体
struct Circle {
double x; // 圆心x坐标
double y; // 圆心y坐标
double r; // 半径
};
// 计算两点之间的距离
double distance(double x1, double y1, double x2, double y2) {
return std::sqrt(std::pow(x2 - x1, 2) + std::pow(y2 - y1, 2));
}
// 计算点到圆心的距离
double distance(double x, double y, Circle circle) {
return std::sqrt(std::pow(x - circle.x, 2) + std::pow(y - circle.y, 2));
}
// RANSAC算法拟合圆形模型
Circle ransac(std::vector<std::pair<double, double>> points, int iterations, double threshold) {
std::random_device rd;
std::mt19937 gen(rd());
std::uniform_int_distribution<> dis(0, points.size() - 1);
Circle best_circle = {0, 0, 0};
int best_count = 0;
for (int i = 0; i < iterations; i++) {
// 随机选择三个点
int idx1 = dis(gen);
int idx2 = dis(gen);
int idx3 = dis(gen);
// 计算圆形参数
double x1 = points[idx1].first;
double y1 = points[idx1].second;
double x2 = points[idx2].first;
double y2 = points[idx2].second;
double x3 = points[idx3].first;
double y3 = points[idx3].second;
double a = x1 - x2;
double b = y1 - y2;
double c = x1 - x3;
double d = y1 - y3;
double e = (std::pow(x1, 2) - std::pow(x2, 2)) + (std::pow(y1, 2) - std::pow(y2, 2));
double f = (std::pow(x1, 2) - std::pow(x3, 2)) + (std::pow(y1, 2) - std::pow(y3, 2));
double delta = a * d - b * c;
if (delta == 0) {
continue;
}
double x0 = (d * e - b * f) / (2 * delta);
double y0 = (a * f - c * e) / (2 * delta);
double r = distance(x0, y0, x1, y1);
// 统计点数
int count = 0;
for (std::pair<double, double> point : points) {
if (distance(point.first, point.second, x0, y0) <= threshold) {
count++;
}
}
// 更新最优圆形
if (count > best_count) {
best_circle.x = x0;
best_circle.y = y0;
best_circle.r = r;
best_count = count;
}
}
return best_circle;
}
int main() {
// 生成随机点
std::vector<std::pair<double, double>> points;
std::random_device rd;
std::mt19937 gen(rd());
std::uniform_real_distribution<> dis(-10, 10);
for (int i = 0; i < 100; i++) {
double x = dis(gen);
double y = dis(gen);
if (std::pow(x, 2) + std::pow(y, 2) <= 25) { // 在圆内的点
points.push_back({x, y});
}
}
// RANSAC拟合圆形模型
Circle circle = ransac(points, 1000, 1);
// 输出结果
std::cout << "Best circle: (" << circle.x << ", " << circle.y << "), r = " << circle.r << std::endl;
return 0;
}
```
该代码通过随机选择三个点计算圆形参数,并统计在圆内的点数。重复此过程若干次后,选取点数最多的圆形作为最优圆形。
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