写一个同时测试annuity\annuityf\annuityl compound\compoundf\compoundl compound\compoundf\compoundl gamma_r\gamma_rf\gamma_rl j1\j1f\j1l jn\jnf\jnl lgamma_r\lgamma_rf\lgamma_rl的案例
时间: 2023-06-29 13:17:55 浏览: 120
假设我们要测试十二个不同的函数:annuity、annuityf、annuityl、compound、compoundf、compoundl、gamma_r、gamma_rf、gamma_rl、j1、j1f、j1l、jn、jnf、jnl、lgamma_r、lgamma_rf、lgamma_rl,下面是一个可能的测试案例:
```c
#include <stdio.h>
#include <math.h>
int main() {
double r = 0.05;
float f = 0.05f;
long double l = 0.05l;
double x = 0.5;
float y = 0.5f;
long double z = 0.5l;
int n = 2;
double result1 = annuity(r, n, x);
float result2 = annuityf(f, n, y);
long double result3 = annuityl(l, n, z);
double result4 = compound(r, n);
float result5 = compoundf(f, n);
long double result6 = compoundl(l, n);
double result7 = gamma_r(x);
float result8 = gamma_rf(y);
long double result9 = gamma_rl(z);
double result10 = j1(x);
float result11 = j1f(y);
long double result12 = j1l(z);
double result13 = jn(n, x);
float result14 = jnf(n, y);
long double result15 = jnl(n, z);
double result16 = lgamma_r(x);
float result17 = lgamma_rf(y);
long double result18 = lgamma_rl(z);
printf("annuity(%.2lf, %d, %.2lf) = %.10lf\n", r, n, x, result1);
printf("annuityf(%.2f, %d, %.2f) = %.10f\n", f, n, y, result2);
printf("annuityl(%.2Lf, %d, %.2Lf) = %.10Lf\n", l, n, z, result3);
printf("compound(%.2lf, %d) = %.10lf\n", r, n, result4);
printf("compoundf(%.2f, %d) = %.10f\n", f, n, result5);
printf("compoundl(%.2Lf, %d) = %.10Lf\n", l, n, result6);
printf("gamma_r(%.2lf) = %.10lf\n", x, result7);
printf("gamma_rf(%.2f) = %.10f\n", y, result8);
printf("gamma_rl(%.2Lf) = %.10Lf\n", z, result9);
printf("j1(%.2lf) = %.10lf\n", x, result10);
printf("j1f(%.2f) = %.10f\n", y, result11);
printf("j1l(%.2Lf) = %.10Lf\n", z, result12);
printf("jn(%d, %.2lf) = %.10lf\n", n, x, result13);
printf("jnf(%d, %.2f) = %.10f\n", n, y, result14);
printf("jnl(%d, %.2Lf) = %.10Lf\n", n, z, result15);
printf("lgamma_r(%.2lf) = %.10lf\n", x, result16);
printf("lgamma_rf(%.2f) = %.10f\n", y, result17);
printf("lgamma_rl(%.2Lf) = %.10Lf\n", z, result18);
return 0;
}
```
在这个案例中,我们使用了三个不同的数据类型以及对应的函数:double、float、long double、annuity、compound、gamma_r、j1、jn、lgamma_r。然后,我们使用相同的输入值来测试这些函数,并将结果打印到屏幕上。在测试annuity、annuityf、annuityl、compound、compoundf、compoundl、j1、j1f、j1l、jn、jnf和jnl时,我们使用一个n值为2的参数。最后,我们返回0表示程序正常结束。
请注意,这只是一个简单的测试案例,实际情况可能会更加复杂。在实际测试中,我们需要考虑更多的因素,例如输入值的范围、边界条件、误差容忍度等等。同时,我们还需要确保我们的测试覆盖了所有可能的代码路径,以尽可能地发现潜在的错误。
阅读全文