供给系统外星人问题的源代码和伪代码

以下是一个简单的供给系统外星人问题的源代码和伪代码：

源代码：

import random

# 定义函数，接受三个参数：食物数量、人口数量、每人每天的平均食量
def calculate_food_supply(food_count, population, avg_food_per_person):
    # 计算每天需要的总食物数量
    total_food_needed = population * avg_food_per_person
    # 如果有足够的食物供应，则返回 "足够" 的字符串
    if food_count >= total_food_needed:
        return "足够"
    # 否则计算缺少的食物数量
    food_shortage = total_food_needed - food_count
    # 计算可以存活的天数
    days_survivable = food_count / (population * avg_food_per_person)
    # 返回字符串，包含缺少的食物数量和可以存活的天数
    return f"缺少 {food_shortage} 单位食物，只能存活 {days_survivable} 天"

# 生成随机的食物数量、人口数量和每人每天的平均食量
food_count = random.randint(100, 1000)
population = random.randint(1, 100)
avg_food_per_person = round(random.uniform(0.5, 3.0), 1)

# 调用函数并打印结果
result = calculate_food_supply(food_count, population, avg_food_per_person)
print(f"食物数量：{food_count}")
print(f"人口数量：{population}")
print(f"每人每天的平均食量：{avg_food_per_person}")
print(f"供给系统状态：{result}")

伪代码：

FUNCTION calculate_food_supply(food_count, population, avg_food_per_person):
    total_food_needed = population * avg_food_per_person
    IF food_count >= total_food_needed THEN
        RETURN "足够"
    ELSE
        food_shortage = total_food_needed - food_count
        days_survivable = food_count / (population * avg_food_per_person)
        RETURN "缺少 " + food_shortage + " 单位食物，只能存活 " + days_survivable + " 天"
    END IF
END FUNCTION

food_count = GENERATE_RANDOM_INTEGER(100, 1000)
population = GENERATE_RANDOM_INTEGER(1, 100)
avg_food_per_person = ROUND(GENERATE_RANDOM_FLOAT(0.5, 3.0), 1)

result = calculate_food_supply(food_count, population, avg_food_per_person)
PRINT("食物数量：" + food_count)
PRINT("人口数量：" + population)
PRINT("每人每天的平均食量：" + avg_food_per_person)
PRINT("供给系统状态：" + result)