def get_url_content(url: object) -> object:这句报错麻烦修改一下
时间: 2024-02-07 14:02:23 浏览: 30
这个错误通常是因为您的代码中使用了不正确的类型注释语法。正确的语法应该是:
```
def get_url_content(url: str) -> str:
# 函数体
```
“->”符号用于指定函数的返回值类型。在这个例子中,我们假设“get_url_content”函数接收一个字符串类型的参数“url”,并返回一个字符串类型的网页内容。
请注意,类型注释只是一种语法糖,在运行时并不会影响程序的执行。如果您的代码中使用了类型注释,但是出现了语法错误,请检查您的注释语法是否正确。
相关问题
def get_university_vec_dict(university_info: dict, refer: dict) -> object:
As an AI language model, I cannot determine the exact implementation details of the function from the given code snippet. However, based on the function signature and the input parameters, I can make an assumption about the purpose of the function.
It seems that the function `get_university_vec_dict()` takes two input parameters - `university_info` and `refer`. `university_info` is a dictionary containing information about universities and `refer` is another dictionary containing reference information.
The function is expected to return an object, which is not specified in the signature. It is likely that the function will return a dictionary containing vectors for each university in `university_info` based on the reference information in `refer`.
The implementation details of how the vectors are calculated and what specific format the output object takes are not clear from the given code snippet.
def get_pub_key(repos: str, token: str) -> tuple[str, int]: TypeError: 'type' object is not subscriptable
这错误通常出现在使用了不支持下标操作的类型。在这个例子中,看起来是使用了类型 `tuple` 来做下标操作,但是 `tuple` 不支持下标操作。
要解决这个问题,需要检查代码中使用了哪些类型,并确认这些类型是否支持下标操作。如果是一个可迭代对象,可以尝试使用 `list()` 或 `tuple()` 函数将其转换为列表或元组来支持下标操作。如果是自定义的类,可以考虑实现 `__getitem__()` 方法来支持下标操作。